zoukankan      html  css  js  c++  java
  • codeforce 621B Wet Shark and Bishops

    对角线 x1+y1=x2+y2 或者x1-y1=x2-y2

     1 #include<iostream>
     2 #include<string>
     3 #include<algorithm>
     4 #include<cstdlib>
     5 #include<cstdio>
     6 #include<set>
     7 #include<map>
     8 #include<vector>
     9 #include<cstring>
    10 #include<stack>
    11 #include<cmath>
    12 #include<queue>
    13 #include <bits/stdc++.h>
    14 using namespace std;
    15 #define INF 0x3f3f3f3f
    16 #define ll long long
    17 #define clc(a,b) memset(a,b,sizeof(a))
    18 const int maxn=4010;
    19 
    20 int main()
    21 {
    22     int n;
    23     int x,y;
    24     int a[maxn];
    25     int b[maxn];
    26     scanf("%d",&n);
    27     clc(a,0);
    28     clc(b,0);
    29     for(int i=0;i<n;i++)
    30     {
    31         scanf("%d%d",&x,&y);
    32         a[x+y]++;
    33         b[x-y+2000]++;
    34     }
    35     ll sum=0;
    36     for(int i=0;i<=2000;i++)
    37     {
    38         if(a[i]%2)
    39             sum+=(a[i]-1)/2*a[i];
    40         else
    41             sum+=a[i]/2*(a[i]-1);
    42     }
    43     for(int i=-999+2000;i<=999+2000;i++)
    44     {
    45         if(b[i]%2)
    46             sum+=(b[i]-1)/2*b[i];
    47         else
    48             sum+=b[i]/2*(b[i]-1);
    49     }
    50     printf("%I64d
    ",sum);
    51     return 0;
    52 }
    View Code
  • 相关阅读:
    1112评论
    1029 C语言文法
    0909编译原理理解和解释
    复利计算4.0-单元测试
    命令解析程序的编写
    《构建之法》1、2、3章思考与感想
    复利计算4.0
    实验三的分析与总结
    复利计算(更新)
    单、复利计算程序
  • 原文地址:https://www.cnblogs.com/ITUPC/p/5175338.html
Copyright © 2011-2022 走看看