zoukankan      html  css  js  c++  java
  • AC日记——[Scoi2010]序列操作 bzoj 1858

    1858

    思路:

      恶心;

    代码:

    #include <bits/stdc++.h>
    using namespace std;
    #define maxn 100005
    struct TreeNodeType { 
        int l,r,l1,r1,m1,l0,r0,m0,mid,size,cnt1,cnt0;
        bool f1,f0,ff;
        inline void turn(){swap(l1,l0),swap(r1,r0),swap(m1,m0),swap(cnt1,cnt0);}
        inline void turn1(){l0=0,r0=0,m0=0,cnt0=0,l1=size,r1=size,m1=size,cnt1=size;}
        inline void turn0(){l1=0,r1=0,m1=0,cnt1=0,l0=size,r0=size,m0=size,cnt0=size;}
        inline void F1(){f1=true,f0=false,ff=false;}
        inline void F0(){f0=true,f1=false,ff=false;}
        inline void FF(){
            if(f1) f0=true,f1=false;
            else if(f0) f1=true,f0=false;
            else ff^=1;
        }
        inline void turnzero(){f1=false,f0=false,ff=false;}
    };
    struct TreeNodeType tree[maxn<<2];
    struct AnsType {
        int l,r,m,s;
    };
    int n,m,Count;
    inline void in(int &now)
    {
        char Cget=getchar();now=0;
        while(Cget>'9'||Cget<'0') Cget=getchar();
        while(Cget>='0'&&Cget<='9') now=now*10+Cget-'0',Cget=getchar();
    }
    inline void updata(int now)
    {
        tree[now].cnt1=tree[now<<1].cnt1+tree[now<<1|1].cnt1;
        tree[now].cnt0=tree[now<<1].cnt0+tree[now<<1|1].cnt0;
        tree[now].l1=tree[now<<1].size==tree[now<<1].l1?tree[now<<1].l1+tree[now<<1|1].l1:tree[now<<1].l1;
        tree[now].l0=tree[now<<1].size==tree[now<<1].l0?tree[now<<1].l0+tree[now<<1|1].l0:tree[now<<1].l0;
        tree[now].r1=tree[now<<1|1].size==tree[now<<1|1].r1?tree[now<<1|1].r1+tree[now<<1].r1:tree[now<<1|1].r1;
        tree[now].r0=tree[now<<1|1].size==tree[now<<1|1].r0?tree[now<<1|1].r0+tree[now<<1].r0:tree[now<<1|1].r0;
        tree[now].m1=max(tree[now<<1].r1+tree[now<<1|1].l1,max(tree[now<<1].m1,tree[now<<1|1].m1));
        tree[now].m0=max(tree[now<<1].r0+tree[now<<1|1].l0,max(tree[now<<1].m0,tree[now<<1|1].m0));
    }
    inline void downdata(int now)
    {
        if(tree[now].f1) tree[now<<1].turn1(),tree[now<<1|1].turn1(),tree[now<<1].F1(),tree[now<<1|1].F1();
        if(tree[now].f0) tree[now<<1].turn0(),tree[now<<1|1].turn0(),tree[now<<1].F0(),tree[now<<1|1].F0();
        if(tree[now].ff) tree[now<<1].turn(),tree[now<<1|1].turn(),tree[now<<1].FF(),tree[now<<1|1].FF();
        tree[now].turnzero();
    }
    inline void build(int now,int l,int r)
    {
        tree[now].l=l,tree[now].r=r,tree[now].size=r-l+1;
        if(l==r)
        {
            int pos;
            in(pos);
            if(pos) tree[now].l1=1,tree[now].r1=1,tree[now].m1=1,tree[now].cnt1=1;
            else tree[now].l0=1,tree[now].r0=1,tree[now].m0=1,tree[now].cnt0=1;
            return;
        }
        tree[now].mid=l+r>>1;
        build(now<<1,l,tree[now].mid);
        build(now<<1|1,tree[now].mid+1,r);
        updata(now);
    }
    inline void operation0(int now,int l,int r)
    {
        if(tree[now].l>=l&&tree[now].r<=r){tree[now].turn0(),tree[now].F0();return;}
        if(tree[now].f1||tree[now].f0||tree[now].ff) downdata(now);
        if(l<=tree[now].mid) operation0(now<<1,l,min(r,tree[now].mid));
        if(r>tree[now].mid) operation0(now<<1|1,max(tree[now].mid+1,l),r);
        updata(now);    
    }
    inline void operation1(int now,int l,int r)
    {
        if(tree[now].l>=l&&tree[now].r<=r){tree[now].turn1(),tree[now].F1();return;}    
        if(tree[now].f1||tree[now].f0||tree[now].ff) downdata(now);
        if(l<=tree[now].mid) operation1(now<<1,l,min(r,tree[now].mid));
        if(r>tree[now].mid) operation1(now<<1|1,max(tree[now].mid+1,l),r);
        updata(now);
    }
    inline void operation2(int now,int l,int r)
    {    
        if(tree[now].l>=l&&tree[now].r<=r){tree[now].turn(),tree[now].FF();return;}    
        if(tree[now].f1||tree[now].f0||tree[now].ff) downdata(now);
        if(l<=tree[now].mid) operation2(now<<1,l,min(r,tree[now].mid));
        if(r>tree[now].mid) operation2(now<<1|1,max(tree[now].mid+1,l),r);
        updata(now);
    }
    inline void operation3(int now,int l,int r)
    {
        if(tree[now].l>=l&&tree[now].r<=r){Count+=tree[now].cnt1;return;}
        if(tree[now].f1||tree[now].f0||tree[now].ff) downdata(now);
        if(l<=tree[now].mid) operation3(now<<1,l,min(r,tree[now].mid));
        if(r>tree[now].mid) operation3(now<<1|1,max(l,tree[now].mid+1),r);
        updata(now);
    }
    inline AnsType operation4(int now,int l,int r)
    {
        if(tree[now].l>=l&&tree[now].r<=r) return (AnsType){tree[now].l1,tree[now].r1,tree[now].m1,tree[now].size};
        if(tree[now].f1||tree[now].f0||tree[now].ff) downdata(now);
        bool al=false,ar=false;AnsType Al,Ar,res;
        if(l<=tree[now].mid) al=true,Al=operation4(now<<1,l,min(r,tree[now].mid));
        if(r>tree[now].mid) ar=true,Ar=operation4(now<<1|1,max(l,tree[now].mid+1),r);
        if(al&&ar)
        {
            res.s=Al.s+Ar.s;
            res.l=Al.s==Al.l?Al.l+Ar.l:Al.l;
            res.r=Ar.s==Ar.r?Ar.r+Al.r:Ar.r;
            res.m=max(Al.r+Ar.l,max(Al.m,Ar.m));
            return res;
        }
        return al?Al:Ar;
    }
    int main()
    {
        in(n),in(m),build(1,0,n-1);
        int op,l,r;AnsType pos;
        while(m--)
        {
            in(op),in(l),in(r);
            if(op==0) operation0(1,l,r);
            if(op==1) operation1(1,l,r);
            if(op==2) operation2(1,l,r);
            if(op==3) Count=0,operation3(1,l,r),printf("%d
    ",Count);
            if(op==4) pos=operation4(1,l,r),printf("%d
    ",max(max(pos.l,pos.r),pos.m));
        }
        return 0;
    }
  • 相关阅读:
    Java实现字符串的包含
    Java实现字符串的包含
    Java实现字符串的包含
    Java实现字符串的包含
    Java实现字符串的包含
    穷文富理撑死工,得先学门能挣钱的手艺
    Windows更新清理工具 (winsxs 清理工具)
    SQLite实现内存键值存储
    Qt5.7.0移植到4412
    罗辑思维2014 第11集 迷茫时代的明白人(慢慢来,能做一点是一点),有书卖
  • 原文地址:https://www.cnblogs.com/IUUUUUUUskyyy/p/6938726.html
Copyright © 2011-2022 走看看