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  • 洛谷3387 【模板】缩点

    原题链接

    做了挺多强连通分量缩点题,结果模板还晾着。。
    (tarjan)找强连通缩点,然后拓扑排序(DP)就好。

    #include<cstdio>
    using namespace std;
    const int N = 1e4 + 10;
    const int M = 1e5 + 10;
    struct eg {
    	int x, y;
    };
    eg a[M];
    int fi[N], di[M], ne[M], cfi[N], cdi[M], cne[M], dfn[N], low[N], sta[N], bl[N], po[N], S[N], ru[N], q[M], su[N], l, lc, tp, ti, SCC, ma;
    bool v[N];
    inline int re()
    {
    	int x = 0;
    	char c = getchar();
    	bool p = 0;
    	for (; c < '0' || c > '9'; c = getchar())
    		p |= c == '-';
    	for (; c >= '0' && c <= '9'; c = getchar())
    		x = x * 10 + c - '0';
    	return p ? -x : x;
    }
    inline void add(int x, int y)
    {
    	di[++l] = y;
    	ne[l] = fi[x];
    	fi[x] = l;
    }
    inline void add_c(int x, int y)
    {
    	cdi[++lc] = y;
    	cne[lc] = cfi[x];
    	cfi[x] = lc;
    }
    inline int minn(int x, int y)
    {
    	return x < y ? x : y;
    }
    inline int maxn(int x, int y)
    {
    	return x > y ? x : y;
    }
    void tarjan(int x)
    {
    	int i, y;
    	dfn[x] = low[x] = ++ti;
    	sta[++tp] = x;
    	v[x] = 1;
    	for (i = fi[x]; i; i = ne[i])
    		if (!dfn[y = di[i]])
    		{
    			tarjan(y);
    			low[x] = minn(low[x], low[y]);
    		}
    		else
    			if (v[y])
    				low[x] = minn(low[x], dfn[y]);
    	if (!(dfn[x] ^ low[x]))
    	{
    		SCC++;
    		do
    		{
    			y = sta[tp--];
    			bl[y] = SCC;
    			v[y] = 0;
    			S[SCC] += po[y];
    		} while (x ^ y);
    		ma = maxn(ma, S[SCC]);
    	}
    }
    void topsort()
    {
    	int i, x, y, head = 0, tail = 0;
    	for (i = 1; i <= SCC; i++)
    		if (!ru[i])
    		{
    			q[++tail] = i;
    			su[i] = S[i];
    		}
    	while (head ^ tail)
    	{
    		x = q[++head];
    		for (i = cfi[x]; i; i = cne[i])
    		{
    			ru[y = cdi[i]]--;
    			if (!ru[y])
    				q[++tail] = y;
    			su[y] = maxn(su[y], su[x] + S[y]);
    			ma = maxn(ma, su[y]);
    		}
    	}
    }
    int main()
    {
    	int i, n, m, x, y;
    	n = re();
    	m = re();
    	for (i = 1; i <= n; i++)
    		po[i] = re();
    	for (i = 1; i <= m; i++)
    	{
    		a[i].x = re();
    		a[i].y = re();
    		add(a[i].x, a[i].y);
    	}
    	for (i = 1; i <= n; i++)
    		if (!dfn[i])
    			tarjan(i);
    	for (i = 1; i <= m; i++)
    	{
    		x = bl[a[i].x];
    		y = bl[a[i].y];
    		if (x ^ y)
    		{
    			add_c(x, y);
    			ru[y]++;
    		}
    	}
    	topsort();
    	printf("%d", ma);
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/Iowa-Battleship/p/9686086.html
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