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  • CF1230E Kamil and Making a Stream

    题目大意是求
    (sum_{v,fa,lca(v,fa)=fa}gcd(v o fa))

    容易发现 (gcd) 只会变小,所以根据这玩意是从上到下的,每次暴力一下就可以了,(gcd)数量不会超过(log),所以复杂度大概是 (n log n)

    // powered by c++11
    // by Isaunoya
    #include <bits/stdc++.h>
    #define rep(i, x, y) for (register int i = (x); i <= (y); ++i)
    #define Rep(i, x, y) for (register int i = (x); i >= (y); --i)
    using namespace std;
    using db = double;
    using ll = long long;
    using uint = unsigned int;
    #define int long long
    using pii = pair<int, int>;
    #define ve vector
    #define Tp template
    #define all(v) v.begin(), v.end()
    #define sz(v) ((int)v.size())
    #define pb emplace_back
    #define fir first
    #define sec second
    // the cmin && cmax
    Tp<class T> void cmax(T& x, const T& y) {
      if (x < y) x = y;
    }
    Tp<class T> void cmin(T& x, const T& y) {
      if (x > y) x = y;
    }
    // sort , unique , reverse
    Tp<class T> void sort(ve<T>& v) { sort(all(v)); }
    Tp<class T> void unique(ve<T>& v) {
      sort(all(v));
      v.erase(unique(all(v)), v.end());
    }
    Tp<class T> void reverse(ve<T>& v) { reverse(all(v)); }
    const int SZ = 0x191981;
    struct FILEIN {
      ~FILEIN() {}
      char qwq[SZ], *S = qwq, *T = qwq, ch;
      char GETC() { return (S == T) && (T = (S = qwq) + fread(qwq, 1, SZ, stdin), S == T) ? EOF : *S++; }
      FILEIN& operator>>(char& c) {
        while (isspace(c = GETC()))
          ;
        return *this;
      }
      FILEIN& operator>>(string& s) {
        while (isspace(ch = GETC()))
          ;
        s = ch;
        while (!isspace(ch = GETC())) s += ch;
        return *this;
      }
      Tp<class T> void read(T& x) {
        bool sign = 1;
        while ((ch = GETC()) < 0x30)
          if (ch == 0x2d) sign = 0;
        x = (ch ^ 0x30);
        while ((ch = GETC()) > 0x2f) x = x * 0xa + (ch ^ 0x30);
        x = sign ? x : -x;
      }
      FILEIN& operator>>(int& x) { return read(x), *this; }
      FILEIN& operator>>(signed& x) { return read(x), *this; }
      FILEIN& operator>>(unsigned& x) { return read(x), *this; }
    } in;
    struct FILEOUT {
      const static int LIMIT = 0x114514;
      char quq[SZ], ST[0x114];
      signed sz, O;
      ~FILEOUT() { flush(); }
      void flush() {
        fwrite(quq, 1, O, stdout);
        fflush(stdout);
        O = 0;
      }
      FILEOUT& operator<<(char c) { return quq[O++] = c, *this; }
      FILEOUT& operator<<(string str) {
        if (O > LIMIT) flush();
        for (char c : str) quq[O++] = c;
        return *this;
      }
      Tp<class T> void write(T x) {
        if (O > LIMIT) flush();
        if (x < 0) {
          quq[O++] = 0x2d;
          x = -x;
        }
        do {
          ST[++sz] = x % 0xa ^ 0x30;
          x /= 0xa;
        } while (x);
        while (sz) quq[O++] = ST[sz--];
        return;
      }
      FILEOUT& operator<<(int x) { return write(x), *this; }
      FILEOUT& operator<<(signed x) { return write(x), *this; }
      FILEOUT& operator<<(unsigned x) { return write(x), *this; }
    } out;
    
    int n, ans;
    const int maxn = 1e5 + 10;
    vector<int> g[maxn];
    int val[maxn];
    int gcd(int x, int y) { return y ? gcd(y, x % y) : x; }
    const int mod = 1e9 + 7;
    void dfs(vector<pii> vc, int u, int p) {
      vector<pii> nvc;
      nvc.pb(val[u], 1ll);
      ans = (ans + val[u]) % mod;
      for (pii x : vc) {
        int y = x.first;
        int c = x.second;
        int ny = gcd(y, val[u]);
        ans = (ans + ny * c) % mod;
        if (ny == nvc.back().first)
          nvc.back().second += c;
        else
          nvc.pb(ny, c);
      }
      nvc.swap(vc);
      for (int v : g[u])
        if (v != p) dfs(vc, v, u);
    }
    signed main() {
    #ifdef _WIN64
      freopen("testdata.in", "r", stdin);
    #else
      ios_base ::sync_with_stdio(false);
      cin.tie(nullptr), cout.tie(nullptr);
    #endif
      // code begin.
      in >> n;
      for (int i = 0; i < n; i++) {
        in >> val[i];
      }
      for (int i = 1; i < n; i++) {
        int u, v;
        in >> u >> v;
        --v, --u;
        g[u].pb(v);
        g[v].pb(u);
      }
      dfs({}, 0, -1);
      out << ans << '
    ';
      return 0;
      // code end.
    }
    
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  • 原文地址:https://www.cnblogs.com/Isaunoya/p/12325603.html
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