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  • P4097 [HEOI2013]Segment [李超树]

    李超树模板,细节有点多。。

    // powered by c++11
    // by Isaunoya
    #include <bits/stdc++.h>
    
    #define rep(i, x, y) for (register int i = (x); i <= (y); ++i)
    #define Rep(i, x, y) for (register int i = (x); i >= (y); --i)
    
    using namespace std;
    using db = double;
    using ll = long long;
    using uint = unsigned int;
    using ull = unsigned long long;
    
    #define pii pair<int, int>
    #define fir first
    #define sec second
    
    template <class T>
    
    void cmax(T& x, const T& y) {
      if (x < y) x = y;
    }
    
    template <class T>
    
    void cmin(T& x, const T& y) {
      if (x > y) x = y;
    }
    
    #define all(v) v.begin(), v.end()
    #define sz(v) ((int)v.size())
    #define pb emplace_back
    
    template <class T>
    
    void sort(vector<T>& v) {
      sort(all(v));
    }
    
    template <class T>
    
    void reverse(vector<T>& v) {
      reverse(all(v));
    }
    
    template <class T>
    
    void unique(vector<T>& v) {
      sort(all(v)), v.erase(unique(all(v)), v.end());
    }
    
    void reverse(string& s) { reverse(s.begin(), s.end()); }
    
    const int io_size = 1 << 23 | 233;
    const int io_limit = 1 << 22;
    struct io_in {
      char ch;
    #ifndef __WIN64
      char getchar() {
        static char buf[io_size], *p1 = buf, *p2 = buf;
    
        return (p1 == p2) && (p2 = (p1 = buf) + fread(buf, 1, io_size, stdin), p1 == p2) ? EOF : *p1++;
      }
    #endif
      io_in& operator>>(char& c) {
        for (c = getchar(); isspace(c); c = getchar())
          ;
    
        return *this;
      }
      io_in& operator>>(string& s) {
        for (s.clear(); isspace(ch = getchar());)
          ;
    
        if (!~ch) return *this;
    
        for (s = ch; !isspace(ch = getchar()) && ~ch; s += ch)
          ;
    
        return *this;
      }
    
      io_in& operator>>(char* str) {
        char* cur = str;
        while (*cur) *cur++ = 0;
    
        for (cur = str; isspace(ch = getchar());)
          ;
        if (!~ch) return *this;
    
        for (*cur = ch; !isspace(ch = getchar()) && ~ch; *++cur = ch)
          ;
    
        return *++cur = 0, *this;
      }
    
      template <class T>
    
      void read(T& x) {
        bool f = 0;
        while ((ch = getchar()) < 48 && ~ch) f ^= (ch == 45);
    
        x = ~ch ? (ch ^ 48) : 0;
        while ((ch = getchar()) > 47) x = x * 10 + (ch ^ 48);
        x = f ? -x : x;
      }
    
      io_in& operator>>(int& x) { return read(x), *this; }
    
      io_in& operator>>(ll& x) { return read(x), *this; }
    
      io_in& operator>>(uint& x) { return read(x), *this; }
    
      io_in& operator>>(ull& x) { return read(x), *this; }
    
      io_in& operator>>(db& x) {
        read(x);
        bool f = x < 0;
        x = f ? -x : x;
        if (ch ^ '.') return *this;
    
        double d = 0.1;
        while ((ch = getchar()) > 47) x += d * (ch ^ 48), d *= .1;
        return x = f ? -x : x, *this;
      }
    } in;
    
    struct io_out {
      char buf[io_size], *s = buf;
      int pw[233], st[233];
    
      io_out() {
        set(7);
        rep(i, pw[0] = 1, 9) pw[i] = pw[i - 1] * 10;
      }
    
      ~io_out() { flush(); }
    
      void io_chk() {
        if (s - buf > io_limit) flush();
      }
    
      void flush() { fwrite(buf, 1, s - buf, stdout), fflush(stdout), s = buf; }
    
      io_out& operator<<(char c) { return *s++ = c, *this; }
    
      io_out& operator<<(string str) {
        for (char c : str) *s++ = c;
        return io_chk(), *this;
      }
    
      io_out& operator<<(char* str) {
        char* cur = str;
        while (*cur) *s++ = *cur++;
        return io_chk(), *this;
      }
    
      template <class T>
    
      void write(T x) {
        if (x < 0) *s++ = '-', x = -x;
    
        do {
          st[++st[0]] = x % 10, x /= 10;
        } while (x);
    
        while (st[0]) *s++ = st[st[0]--] ^ 48;
      }
    
      io_out& operator<<(int x) { return write(x), io_chk(), *this; }
    
      io_out& operator<<(ll x) { return write(x), io_chk(), *this; }
    
      io_out& operator<<(uint x) { return write(x), io_chk(), *this; }
    
      io_out& operator<<(ull x) { return write(x), io_chk(), *this; }
    
      int len, lft, rig;
    
      void set(int _length) { len = _length; }
    
      io_out& operator<<(db x) {
        bool f = x < 0;
        x = f ? -x : x, lft = x, rig = 1. * (x - lft) * pw[len];
        return write(f ? -lft : lft), *s++ = '.', write(rig), io_chk(), *this;
      }
    } out;
    #define int long long
    
    template <int sz, int mod>
    
    struct math_t {
      math_t() {
        fac.resize(sz + 1), ifac.resize(sz + 1);
        rep(i, fac[0] = 1, sz) fac[i] = fac[i - 1] * i % mod;
    
        ifac[sz] = inv(fac[sz]);
        Rep(i, sz - 1, 0) ifac[i] = ifac[i + 1] * (i + 1) % mod;
      }
    
      vector<int> fac, ifac;
    
      int qpow(int x, int y) {
        int ans = 1;
        for (; y; y >>= 1, x = x * x % mod)
          if (y & 1) ans = ans * x % mod;
        return ans;
      }
    
      int inv(int x) { return qpow(x, mod - 2); }
    
      int C(int n, int m) {
        if (n < 0 || m < 0 || n < m) return 0;
        return fac[n] * ifac[m] % mod * ifac[n - m] % mod;
      }
    };
    
    int gcd(int x, int y) { return !y ? x : gcd(y, x % y); }
    int lcm(int x, int y) { return x * y / gcd(x, y); }
    
    int n, m, ans;
    const int maxn = 1e5 + 51;
    const double eps = 1e-8;
    
    int a[maxn], f[maxn];
    struct Line {
      double k, b;
      inline double val(double x) { return k * x + b; }
    } s[maxn];
    
    struct SMT {
      int f[maxn << 2];
    
      void mdf(int ql, int qr, int l, int r, int p, int x) {
        int mid = l + r >> 1;
        if (ql <= l && r <= qr) {
          int y = f[p];
          if (y == 0) {
            f[p] = x;
            return;
          }
          double lx, ly, rx, ry;
          lx = s[x].val(l), rx = s[x].val(r);
          ly = s[y].val(l), ry = s[y].val(r);
          if (abs(lx - ly) <= eps && abs(rx - ry) <= eps) {
            f[p] = min(x, y);
            return;
          }
          if (lx <= ly && rx <= ry) {
            return;
          }
          if (lx >= ly && rx >= ry) {
            f[p] = x;
            return;
          }
          double midx = s[x].val(mid), midy = s[y].val(mid);
          if (abs(midx - midy) <= eps) {
            f[p] = min(x, y), x = max(x, y);
          } else if (midx >= midy) {
            f[p] = x, x = y, swap(lx, ly), swap(rx, ry);
          }
          if (lx >= ly)
            mdf(ql, qr, l, mid, p << 1, x);
          else
            mdf(ql, qr, mid + 1, r, p << 1 | 1, x);
          return;
        }
        if (ql <= mid) mdf(ql, qr, l, mid, p << 1, x);
        if (qr > mid) mdf(ql, qr, mid + 1, r, p << 1 | 1, x);
      }
    
      int qry(int p, int l, int r, int pos) {
        if (l == r) return f[p];
        int mid = l + r >> 1;
        int x, y = f[p];
        if (pos <= mid)
          x = qry(p << 1, l, mid, pos);
        else
          x = qry(p << 1 | 1, mid + 1, r, pos);
        if (x == 0 || y == 0) return x + y;
        double valx = s[x].val(pos);
        double valy = s[y].val(pos);
        if (abs(valx - valy) <= eps) {
          return min(x, y);
        }
        return (valx >= valy) ? x : y;
      }
    } smt;
    
    signed main() {
      // code begin.
      memset(a, 128, sizeof(a));
      n = 1;
      in >> m;
      while (m--) {
        int op;
        in >> op;
        if (op == 1) {
          int sx, sy, tx, ty;
          in >> sx >> sy >> tx >> ty;
          sx = (sx + ans - 1) % 39989;
          sy = (sy + ans - 1) % 1000000000;
          tx = (tx + ans - 1) % 39989;
          ty = (ty + ans - 1) % 1000000000;
          if (sx == tx) {
            if (a[sx] < max(sy, ty)) {
              a[sx] = max(sy, ty), f[sx] = n;
            }
          } else {
            if (sx > tx) {
              sx ^= tx ^= sx ^= tx, sy ^= ty ^= sy ^= ty;
            }
            s[n].k = 1.0 * (ty - sy) / (tx - sx);
            s[n].b = sy - s[n].k * sx;
            smt.mdf(sx, tx, 0, 4e4, 1, n);
          }
          ++n;
        } else {
          int x;
          in >> x;
          x = (x + ans - 1) % 39989;
          ans = smt.qry(1, 0, 4e4, x);
          if (ans == 0) {
            ans = f[x];
          } else if (abs(s[ans].val(x) - a[x]) <= eps) {
            ans = min(ans, f[x]);
          } else {
            ans = s[ans].val(x) >= a[x] ? ans : f[x];
          }
          out << ans << '
    ';
        }
      }
      return 0;
      // code end.
    }
    
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  • 原文地址:https://www.cnblogs.com/Isaunoya/p/12820281.html
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