zoukankan      html  css  js  c++  java
  • BZOJ 1624: [Usaco2008 Open] Clear And Present Danger 寻宝之路( 最短路 )

    直接floyd..

    -----------------------------------------------------------------------

    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    #include<iostream>
    #include<vector>
     
    #define rep( i , n ) for( int i = 0 ; i < n ; ++i )
    #define clr( x , c ) memset( x ,c , sizeof( x ) )
    #define Rep( i , n ) for( int i = 1 ; i <= n ; ++i )
     
    using namespace std;
     
    const int maxn = 100 + 5;
     
    int d[ maxn ][ maxn ];
     
    vector< int > path;
     
    int main() {
    // freopen( "test.in" , "r" , stdin );
    int n , m;
    cin >> n >> m;
    path.clear();
    while( m-- ) {
    int t;
    scanf( "%d" , &t );
    path.push_back ( t - 1 );
    }
    rep( i , n )
       rep( j , n ) scanf( "%d" , &d[ i ][ j ] );
       
    rep( k , n )
       rep( i , n )
           rep( j , n )
               d[ i ][ j ] = min( d[ i ][ j ] , d[ i ][ k ] + d[ k ][ j ] );
    int ans = 0;
    int start = path[ 0 ];
    Rep( i , path.size() - 1 )
    ans += d[ start ][ path[ i ] ] , start = path[ i ];
    cout << ans << " ";
    return 0;
    }

    ----------------------------------------------------------------------- 

    1624: [Usaco2008 Open] Clear And Present Danger 寻宝之路

    Time Limit: 5 Sec  Memory Limit: 64 MB
    Submit: 403  Solved: 282
    [Submit][Status][Discuss]

    Description

        农夫约翰正驾驶一条小艇在牛勒比海上航行.
        海上有N(1≤N≤100)个岛屿,用1到N编号.约翰从1号小岛出发,最后到达N号小岛.一
    张藏宝图上说,如果他的路程上经过的小岛依次出现了Ai,A2,…,AM(2≤M≤10000)这样的序列(不一定相邻),那他最终就能找到古老的宝藏.  但是,由于牛勒比海有海盗出没.约翰知道任意两个岛屿之间的航线上海盗出没的概率,他用一个危险指数Dij(0≤Dij≤100000)来描述.他希望他的寻宝活动经过的航线危险指数之和最小.那么,在找到宝藏的前提下,这个最小的危险指数是多少呢?

    Input

        第1行输入N和M,之后M行一行一个整数表示A序列,之后输入一个NxN的方阵,表示两两岛屿之间航线的危险指数.数据保证Dij=Dji,Dii=0.

    Output

     
        最小的危险指数和.

    Sample Input

    3 4
    1
    2
    1
    3
    0 5 1
    5 0 2
    1 2 0

    INPUT DETAILS:

    There are 3 islands and the treasure map requires Farmer John to
    visit a sequence of 4 islands in order: island 1, island 2, island
    1 again, and finally island 3. The danger ratings of the paths are
    given: the paths (1, 2); (2, 3); (3, 1) and the reverse paths have
    danger ratings of 5, 2, and 1, respectively.


    Sample Output

    7

    OUTPUT DETAILS:

    He can get the treasure with a total danger of 7 by traveling in
    the sequence of islands 1, 3, 2, 3, 1, and 3. The cow map's requirement
    (1, 2, 1, and 3) is satisfied by this route. We avoid the path
    between islands 1 and 2 because it has a large danger rating.

    HINT

    Source

  • 相关阅读:
    提交订单的时候,实现拦截,登录成功后跳转回之前的页面;使用redis生成指定起始位置的id
    iOS Outlets Referencing Outlets
    iOS 常用控件 参数
    iOS UIImageView设置为圆形
    iOS Xcode个人常用插件
    iOS Xcode注释的几种使用方法
    MFC MSBDutyTable下载地址
    MFC HTTP访问URL
    MFC 程序以管理员权限运行
    MFC 打开文件夹选择框并获取文件夹路径
  • 原文地址:https://www.cnblogs.com/JSZX11556/p/4553169.html
Copyright © 2011-2022 走看看