zoukankan      html  css  js  c++  java
  • 3890: [Usaco2015 Jan]Meeting Time( dp )

     简单的拓扑图dp..

    A(i, j), B(i, j) 表示从点 i 长度为 j 的两种路径是否存在. 用bitset就行了  

    时间复杂度O(m) 

    ----------------------------------------------------------------

    #include<bits/stdc++.h>
     
    #define clr(x, c) memset(x, c, sizeof(x))
    #define rep(i, n) for(int i = 0; i < n; ++i)
    #define foreach(i, x) for(__typeof(x.begin()) i = x.begin(); i != x.end(); i++)
     
    using namespace std;
     
    const int maxn = 109;
     
    struct edge {
    int to, a, b;
    };
     
    vector<edge> G[maxn];
    queue<int> Q;
    bitset<10009> A[maxn], B[maxn];
    int n, inD[maxn] = {0};
     
    int main() {
    freopen("test.in", "r", stdin);
    int m;
    cin >> n >> m;
    while(m--) {
    int u, v, a, b;
    scanf("%d%d%d%d", &u, &v, &a, &b); u--; v--;
    G[u].push_back( (edge) {v, a, b} );
    inD[v]++;
    }
    rep(i, n) {
       if(!inD[i]) Q.push(i);
    A[i].reset(); B[i].reset();
    }
    A[0][0] = 1; B[0][0] = 1;
    while(!Q.empty()) {
    int x = Q.front(); Q.pop();
    foreach(it, G[x]) {
    A[it->to] |= A[x] << it->a;
    B[it->to] |= B[x] << it->b;
    if(!--inD[it->to]) Q.push(it->to);
    }
    }
    int ans = -1;
    rep(i, 10001) if(A[n - 1][i] && B[n - 1][i]) {
       ans = i;
       break;
    }
    if(!~ans)
       puts("IMPOSSIBLE");
    else
       printf("%d ", ans);
    return 0;
    }

    ---------------------------------------------------------------- 

    3890: [Usaco2015 Jan]Meeting Time

    Time Limit: 10 Sec  Memory Limit: 128 MB
    Submit: 95  Solved: 65
    [Submit][Status][Discuss]

    Description

    Bessie and her sister Elsie want to travel from the barn to their favorite field, such that they leave at exactly the same time from the barn, and also arrive at exactly the same time at their favorite field. The farm is a collection of N fields (1 <= N <= 100) numbered 1..N, where field 1 contains the barn and field N is the favorite field. The farm is built on the side of a hill, with field X being higher in elevation than field Y if X < Y. An assortment of M paths connect pairs of fields. However, since each path is rather steep, it can only be followed in a downhill direction. For example, a path connecting field 5 with field 8 could be followed in the 5 -> 8 direction but not the other way, since this would be uphill. Each pair of fields is connected by at most one path, so M <= N(N-1)/2. It might take Bessie and Elsie different amounts of time to follow a path; for example, Bessie might take 10 units of time, and Elsie 20. Moreover, Bessie and Elsie only consume time when traveling on paths between fields -- since they are in a hurry, they always travel through a field in essentially zero time, never waiting around anywhere. Please help determine the shortest amount of time Bessie and Elsie must take in order to reach their favorite field at exactly the same moment.
    给出一个n个点m条边的有向无环图,每条边两个边权。 
    n<=100,没有重边。 
    然后要求两条长度相同且尽量短的路径, 
    路径1采用第一种边权,路径2采用第二种边权。 
    没有则输出”IMPOSSIBLE”

    Input

    The first input line contains N and M, separated by a space. Each of the following M lines describes a path using four integers A B C D, where A and B (with A < B) are the fields connected by the path, C is the time required for Bessie to follow the path, and D is the time required for Elsie to follow the path. Both C and D are in the range 1..100.

    Output

    A single integer, giving the minimum time required for Bessie and Elsie to travel to their favorite field and arrive at the same moment. If this is impossible, or if there is no way for Bessie or Elsie to reach the favorite field at all, output the word IMPOSSIBLE on a single line.

    Sample Input

    3 3
    1 3 1 2
    1 2 1 2
    2 3 1 2

    Sample Output

    2

    SOLUTION NOTES:

    Bessie is twice as fast as Elsie on each path, but if Bessie takes the
    path 1->2->3 and Elsie takes the path 1->3 they will arrive at the
    same time.

    HINT

    Source

  • 相关阅读:
    关于一些Spring MVC控制器的参数注解总结
    如何制作知识图谱
    关于本体的一些知识需要了解
    分享一些关于Lucene的心得
    java.lang.NoClassDefFoundError: javax/servlet/jsp/jstl/core/Config
    JAVA小游戏之两个物体碰撞产生的碰撞检测
    IT界程序员几大恶习能立即让你变穷,你有吗?
    JAVA图形界面常用知识点总会《代码分析》
    程序员解决问题的60个策略
    app微信支付-java服务端接口 支付-查询-退款
  • 原文地址:https://www.cnblogs.com/JSZX11556/p/4681155.html
Copyright © 2011-2022 走看看