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  • 863. All Nodes Distance K in Binary Tree

    /**
     * Definition for a binary tree node.
     * struct TreeNode {
     *     int val;
     *     TreeNode *left;
     *     TreeNode *right;
     *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
     * };
     */
    class Solution {
    public:
        vector<int> distanceK(TreeNode* root, TreeNode* target, int K) {
            vector<bool> visited(501, false);
            vector<unordered_set<int>> g(501);
            
            dfs(root, g);
            
            vector<int> res;
            queue<int> q;
            q.push(target->val);
            visited[target->val] = true;
            int lv = 0;
            while (!q.empty()) {
                int qs = q.size();
                if (lv == K) {
                    while(!q.empty()) {
                        res.push_back(q.front());
                        q.pop();
                    }
                    break;
                }
                while (qs-- > 0) {
                    int p = q.front();
                    q.pop();
                    for (auto i : g[p]) {
                        if (!visited[i]) {
                            q.push(i);
                            visited[i] = true;
                        }
                    }
                }
                lv++;
            }
            return res;
        }
        void dfs(TreeNode *root, vector<unordered_set<int>>& g) {
            if (root == NULL)   return;
            if (root->left) {
                g[root->val].insert(root->left->val);
                g[root->left->val].insert(root->val);
            }
            if (root->right) {
                g[root->val].insert(root->right->val);
                g[root->right->val].insert(root->val);
            }
            dfs(root->left, g);
            dfs(root->right, g);
        }
    };
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  • 原文地址:https://www.cnblogs.com/JTechRoad/p/10064629.html
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