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  • sql

    1. 选出某个条件最新的一条记录

    // 选出最新状态下的每一个单号对应的子单数据
    select
    distinct a.receiving_code,a.product_barcode,a.rd_putaway_qty from odoo_ykd_oversea_shipping_information a inner join odoo_ykd_receiving_order_manage b on a.receiving_code=b.receiving_code and a.data_version=b.data_version inner join odoo_sync_control_scrapy c on b.data_version=c.data_version inner join   (select max(a.odoo_create_time) as odoo_create_time, a.receiving_code
      from odoo_ykd_receiving_order_manage a
      inner join odoo_sync_control_scrapy b on b.data_version=a.data_version
      where a.odoo_create_time < '2020-11-19' group by a.receiving_code) as d
      on d.receiving_code=b.receiving_code and d.odoo_create_time=b.odoo_create_time where c.task_type=1 and c.task_status=2 and c.result_type=1 and c.record_status=1 and c.data_date <= '2020-11-18' and c.data_date > '2020-08-10'

    // 或者用这种方式,没写完整,自己补充
    with res as(
    select id,consignment_no, row_number()over(partition by b.consignment_no order by b.odoo_create_time desc) as row_n from odoo_dsf_inbound_order_info)
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  • 原文地址:https://www.cnblogs.com/JackShi/p/14010570.html
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