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  • MySQL多表数据记录查询(二)

    (1)子查询概念

    子查询也称嵌套查询,就是指一个查询之中嵌套了其他的若干查询,即在一个select语句中的where或者from字句中包含一个select查询语句。在查询语句中,外层select查询语句称为主查询,where字句中的select查询语句被称为子查询。

    (2)联合查询概念

    使用union关键字可以把来自多个select语句的结果组合到一个结果集中,这种查询方式称为并(union)运算或联合查询。合并时,多个select字句中对应的字段数和数据类型必须相同。

    1.1、带in关键字的子查询:

    带in关键字的子查询是最常用的一类子查询,1)用于判定一个给定值是否存在于子查询的结果集中。2)使用in关键字进行子查询时,内层查询语句仅仅返回一个数据列,其值将提供给外层查询进行比较操作;

    1:查询选修了课程的学生姓名;(in查询)

    select a.studentName
    
        -> from tb_student as a
    
        -> where a.studentNo in
    
    -> (select distinct tb_score.studentNo from tb_score);
    
    先查内层:
    
    select distinct tb_score.studentNo from tb_score;

    再外层查询;

    练习:

    例12:P96

    查询选修了"计算机基础"和"管理学"的学生学号;

    select tb_score.studentNo
    
         from tb_score,tb_course
    
         where tb_score.courseNo=tb_course.courseNo and tb_course.courseName="计算机基础"
    
         and tb_score.studentNo in
    
         (select studentNo from tb_score,tb_course
    
         where tb_score.courseNo=tb_course.courseNo and tb_course.courseName="管理学");

    2:P89(not in查询)

    查询没有选修过课程的学生学号和学生姓名;

     select a.studentNo,a.studentName
    
        -> from tb_student as a
    
        -> where a.studentNo not in
    
        -> (select distinct tb_score.studentNo from tb_score);

    结果:林海

    练习;

    查询选修了"计算机基础"但是没有选修"管理学"的学生学号

    select tb_score.studentNo
    
         from tb_score,tb_course
    
         where tb_score.courseNo=tb_course.courseNo and tb_course.courseName="计算机基础"
    
         and tb_score.studentNo not in
    
         (select studentNo from tb_score,tb_course
    
         where tb_score.courseNo=tb_course.courseNo and tb_course.courseName="管理学");

    1.2、带比较运算符的子查询:

    带比较运算符的子查询是指1)父查询与子查询之间用比较运算符进行连接。2)当用户能确切知道内层返回的是单值时,3)可以用<,<=,>,>=,=,<>,!=等比较运算符构造子查询;

    3:查询班级"计算机14-1班"所有学生的学号、姓名;

    select a.studentNo,a.studentName
    
        -> from tb_student as a
    
        -> where a.classNo=
    
    -> (select tb_class.ClassNo from tb_class where ClassName="计算机14-1班");
    
    先进行内层查询:
    
    select tb_class.ClassNo from tb_class where ClassName="计算机14-1班";

    结果:CS1401

    再外层查询:

    select a.studentNo,a.studentName
    
        -> from tb_student as a
    
    -> where a.classNo="CS1401";

    思考:

    使用连接查询怎么查?

    select a.studentNo,a.studentName
    
        -> from tb_student as a,tb_class as b
    
        -> where a.classNo=b.ClassNo
    
    -> and b.ClassName="计算机14-1班";

    4:查询与"李明"在同一个班学习的学生学号、姓名、班号;(tb_student)

    select a.studentNo,a.studentName,a.classNo
    
        -> from tb_student as a
    
        -> where a.classNo=
    
        -> (select b.classNo from tb_student as b where b.studentName="李明") and a.studentName!="李明";

    思考:该查询也是自连接查询,连接语句怎么写?

    select a.studentNo,a.studentName,a.classNo
    
        -> from tb_student as a,tb_student as b
    
        -> where a.classNo=b.classNo
    
    -> and b.studentName="李明" and a.studentName!="李明";

    any比较:

    例5:P91,//any比较

    查询男生中比某个女生出生晚的学生姓名和出生年份:

    select a.studentName,year(birthday)
    
    -> from tb_student as a
    
    -> where a.sex="男" and year(birthday)>any
    
    -> (select year(birthday) from tb_student where sex="女");

    用聚合函数语句:min

     select a.studentName,year(birthday)
    
    -> from tb_student as a
    
    -> where a.sex="男" and year(birthday)>
    
    -> (select min(year(birthday)) from tb_student where sex="女" );

    6:,//all比较:

    查询男生中比所有女生出生晚的学生姓名和出生年份:

    select a.studentName,year(a.birthday)
    
    -> from tb_student as a
    
    -> where a.sex="男" and year(a.birthday)>all
    
    -> (select year(birthday) from tb_student where sex="女");

    用聚合函数写:max

     select a.studentName,year(birthday)
    
    -> from tb_student as a
    
    -> where a.sex="男" and year(birthday)>
    -> (select max(year(birthday)) from tb_student where sex="女" );

    1.3、带exists关键字的子查询:

    使用关键字exists构造子查询时,1)系统对子查询进行运算判断它是否返回结果集。2)由于带exists的子查询只返回true或false,内层查询的select子句给出的字段名没有实际意义,所以目标列表达式通常用星号*。

    7:P92,关键字exists查询

    查询选修了课程号为"31002"的学生姓名;

     select a.studentName
    
        -> from tb_student as a
    
        -> where exists
    
        -> (select * from tb_score as b where a.studentNo=b.studentNo and b.courseNo="31002");

    用in查询:

     select a.studentName
    
    -> from tb_student as a
    
    -> where a.studentNo in
    
    -> (select studentNo from tb_score where courseNo="31002");

    8:P93,//关键字not exists查询

    查询没有选修课程号为"31002"的学生姓名;

     select a.studentName
    
        -> from tb_student as a
    
        -> where not exists
    
        -> (select * from tb_score as b where a.studentNo=b.studentNo and b.courseNo="31002");

    用in查询:

     select a.studentName
    
        -> from tb_student as a
    
        -> where a.studentNo not in
    
        -> (select studentNo from tb_score where courseNo="31002");

    9:exists成对使用,双重否定表示肯定

    查询选修了全部课程的学生姓名;

    思路:

    查询这样一个学生,没有一门课是他没有选修的;

    select a.studentName
    
        -> from tb_student as a
    
        -> where not exists
    
        -> (select * from tb_course as b
    
        -> where not exists
    
        -> (select * from tb_score as c
    
    -> where c.courseNo=b.courseNo and a.studentNo=c.studentNo));

    结果:没有这样的学生;empty set

    看一共有几门课:(以课程分组)

    select tb_score.courseNo,count(*)
    
        -> from tb_score
    
        -> group by courseNo;
    
    +----------+----------+
    
    | courseNo | count(*) |
    
    +----------+----------+
    
    |    11003 |        4 |
    
    |    21001 |        6 |
    
    |    21002 |        2 |
    
    |    21004 |        6 |
    
    |    31002 |        2 |
    
    |    44444 |        1 |
    
    +----------+----------+
    
    6 rows in set (0.06 sec)
    
     select tb_score.studentNo,count(courseNo)
    
        -> from tb_score
    
        -> group by studentNo;
    
    +------------+-----------------+
    
    | studentNo  | count(courseNo) |
    
    +------------+-----------------+
    
    | 2013110101 |               2 |
    
    | 2013110103 |               2 |
    
    | 2013110201 |               2 |
    
    | 2013110202 |               2 |
    
    | 2013310101 |               2 |
    
    | 2013310103 |               2 |
    
    | 2014210101 |               2 |
    
    | 2014210102 |               2 |
    
    | 2014310101 |               2 |
    
    | 2014310102 |               2 |
    
    +------------+-----------------+
    
    10 rows in set (0.00 sec)

    联合查询:

    1)使用union关键字可以把多个来自select语句的结果组合到一个结果集中,这种查询方式称为并(union)运算或联合查询。

    2)合并时,多个select字句中对应的字段数和数据类型必须相同。

    3)语法:

    Select-from-where
    
    Union[all]
    
    Select-from-where
    
    [...union[all]]
    
    Select-from-where
    
    Union查询:

    10:union用法,unoin去重了;

    使用union查询选修了"管理学"或"计算机基础"的学生学号;

     select tb_score.studentNo
    
        -> from tb_score,tb_course
    
        -> where tb_score.courseNo=tb_course.courseNo and tb_course.courseName="计
    
    算机基础"
    
        -> union
    
        -> select tb_score.studentNo
    
        -> from tb_score,tb_course
    
        -> where tb_score.courseNo=tb_course.courseNo and tb_course.courseName="管
    
    理学";

    用连接语句查询:使用distinct去重

     select distinct tb_score.studentNo
    
        -> from tb_score,tb_course
    
        -> where tb_score.courseNo=tb_course.courseNo
    
    -> and (tb_course.courseName="管理学" or tb_course.courseName="计算机基础");

    Union all查询:

    11:union all

    使用union all查询选修了"管理学"或"计算机基础"的学生学号;

     select tb_score.studentNo
    
        -> from tb_score,tb_course
    
        -> where tb_score.courseNo=tb_course.courseNo and tb_course.courseName="计
    
    算机基础"
    
        -> union all
    
        -> select tb_score.studentNo
    
        -> from tb_score,tb_course
    
        -> where tb_score.courseNo=tb_course.courseNo and tb_course.courseName="管
    
    理学";

    用连接语句查询://不用distinct去重;

     select tb_score.studentNo
    
        -> from tb_score,tb_course
    
        -> where tb_score.courseNo=tb_course.courseNo
    
        -> and (tb_course.courseName="管理学" or tb_course.courseName="计算机基础");
     
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  • 原文地址:https://www.cnblogs.com/Jackbk/p/12693354.html
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