之前,同事在编写视图的过程中遇到这样了这个错误。我把简化后的语句整理如下:
1: select2: '2016' as nf,
3: qxdm,4: round(sum(tbdlmj)/10000,2) as csydmj--单位转换,2位小数
5: from dltb_2016@dblink_td_tdxz m where dlmc='城市'
6: group by m.qxdm order by m.qxdm 7: 8: union all 9: 10: select11: '2017' as nf,
12: qxdm,13: round(sum(tbdlmj)/10000,2) as csydmj--单位转换,2位小数
14: from dltb_2017@dblink_td_tdxz n where dlmc='城市'
15: group by n.qxdm order by n.qxdm主要是查询各个管辖区中2016年和2017年地类图斑数据中城市用地的面积,语句分单块均可以执行成功,但是使用UNION后则出现ora-00933错误。
检查了列的数量、数据格式均保持一致,没有不对应的现象。
追查了一下原因,最终发现是union和order by字句引起的。
最终处理方式参考如下:
1、如果排序没必要,可以直接去掉,或者在union后统一排序
1: select2: '2016' as nf,
3: qxdm,4: round(sum(tbdlmj)/10000,2) as csydmj--单位转换,2位小数
5: from dltb_2016@dblink_td_tdxz m where dlmc='城市'
6: group by m.qxdm 7: 8: union all 9: 10: select11: '2017' as nf,
12: qxdm,13: round(sum(tbdlmj)/10000,2) as csydmj--单位转换,2位小数
14: from dltb_2017@dblink_td_tdxz n where dlmc='城市'
15: group by n.qxdm或者
1: select2: '2016' as nf,
3: qxdm,4: round(sum(tbdlmj)/10000,2) as csydmj--单位转换,2位小数
5: from dltb_2016@dblink_td_tdxz m where dlmc='城市'
6: group by m.qxdm 7: 8: union all 9: 10: select11: '2017' as nf,
12: qxdm,13: round(sum(tbdlmj)/10000,2) as csydmj--单位转换,2位小数
14: from dltb_2017@dblink_td_tdxz n where dlmc='城市'
15: group by n.qxdm order by qxdm2、可以再嵌套一层查询
1: select * from ( 2: select3: '2016' as nf,
4: qxdm,5: round(sum(tbdlmj)/10000,2) as csydmj--单位转换,2位小数
6: from dltb_2016@dblink_td_tdxz m where dlmc='城市'
7: group by m.qxdm order by m.qxdm 8: ) 9: 10: union all 11: 12: select * from ( 13: select14: '2017' as nf,
15: qxdm,16: round(sum(tbdlmj)/10000,2) as csydmj--单位转换,2位小数
17: from dltb_2017@dblink_td_tdxz n where dlmc='城市'
18: group by n.qxdm order by n.qxdm 19: )或者
1: with2: s1 as (
3: select4: '2016' as nf,
5: qxdm,6: round(sum(tbdlmj)/10000,2) as csydmj--单位转换,2位小数
7: from dltb_2016@dblink_td_tdxz m where dlmc='城市'
8: group by m.qxdm order by m.qxdm 9: ),10: s2 as (
11: select12: '2017' as nf,
13: qxdm,14: round(sum(tbdlmj)/10000,2) as csydmj--单位转换,2位小数
15: from dltb_2017@dblink_td_tdxz n where dlmc='城市'
16: group by n.qxdm order by n.qxdm 17: ) 18: select * from s1 19: union all 20: select * from s2;