zoukankan      html  css  js  c++  java
  • LeetCode 45

    Jump Game II

    Given an array of non-negative integers,
    you are initially positioned at the first index of the array.

    Each element in the array represents your maximum jump length at that position.

    Your goal is to reach the last index in the minimum number of jumps.

    For example:
    Given array A = [2,3,1,1,4]

    The minimum number of jumps to reach the last index is 2.
    (Jump 1 step from index 0 to 1, then 3 steps to the last index.)

     1 /*************************************************************************
     2     > File Name: LeetCode045.c
     3     > Author: Juntaran
     4     > Mail: JuntaranMail@gmail.com
     5     > Created Time: Tue 13 May 2016 14:47:33 PM CST
     6  ************************************************************************/
     7  
     8 /*************************************************************************
     9     
    10     Jump Game II
    11     
    12     Given an array of non-negative integers, 
    13     you are initially positioned at the first index of the array.
    14 
    15     Each element in the array represents your maximum jump length at that position.
    16 
    17     Your goal is to reach the last index in the minimum number of jumps.
    18 
    19     For example:
    20     Given array A = [2,3,1,1,4]
    21 
    22     The minimum number of jumps to reach the last index is 2. 
    23     (Jump 1 step from index 0 to 1, then 3 steps to the last index.)
    24 
    25  ************************************************************************/
    26 
    27 #include <stdio.h>
    28 
    29 int jump(int* nums, int numsSize) 
    30 {
    31     if( numsSize <= 1 )
    32     {
    33         return 0;
    34     }
    35     
    36     int left = nums[0];
    37     int right = nums[0];
    38     int count = 1;
    39     int max = 0;
    40     
    41     int i;
    42     for( i=1; i<numsSize; i++ )
    43     {
    44         if( i > left )
    45         {
    46             left = right;
    47             count ++;
    48         }
    49         right = (i+nums[i])>right ? (i+nums[i]) : right;
    50         if( left >= numsSize-1 )
    51         {
    52             return count;
    53         }
    54     }
    55     return 0;
    56 }
    57 
    58 int main()
    59 {
    60     int nums[] = {2,3,1,1,4};
    61     int numsSize = 5;
    62     
    63     int ret = jump( nums, numsSize );
    64     printf("%d
    ", ret);
    65     
    66     return 0;
    67 }
  • 相关阅读:
    面向对象设计模式之Facade外观模式(结构型)
    Android 多线程:使用Thread和Handler
    Android源码分析之Handler
    Android View的几个位置坐标关系
    LinearLayout布局问题
    Android app被系统kill的场景
    改变Activity启动时的默认动画
    ViewStub源码分析
    Android measure过程分析
    点击ViewGroup时其子控件也变成pressed状态的原因分析及解决办法
  • 原文地址:https://www.cnblogs.com/Juntaran/p/5511669.html
Copyright © 2011-2022 走看看