[VJ]输出m/n，若是循环体只输出第一节

扩充到任意的m和n.

#include<iostream>
#include<cstdio>
#include<string>
#include<string.h>
using namespace std;
int main()
{
    int m, n;
    cin >> m >> n;
    int yu[15], xiao[600];
    memset(yu,0,sizeof(yu));
    if (m < 0 && n>0) { cout << "-";    m = -m; }
    else if (m > 0 && n < 0) { cout << "-";    n = -n; }
    int k = m % n;
    if(k==0)    cout << m / n << endl;
    else {
        cout<<m/n<< ".";
        int cnt = 0;
        yu[k] = 1;
        while (k) {
            k = k * 10;
            xiao[++cnt] = k / n;
            k %= n;
            if (yu[k] == 1)    break;
            yu[k] = 1;
        }
        for (int i = 1; i <= cnt; i++)
            cout << xiao[i];
        cout << endl;
    }
    return 0;
}