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  • [leetcode]2. Add Two Numbers

     2. Add Two Numbers

    You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

    Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
    Output: 7 -> 0 -> 8

    /**
     * Definition for singly-linked list.
     * struct ListNode {
     *     int val;
     *     ListNode *next;
     *     ListNode(int x) : val(x), next(NULL) {}
     * };
     */
    class Solution {
    public:
        ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {
            int take=0;     //represent the carry
            if(l1==NULL||l2==NULL)
                return l1?l1:l2;
            ListNode* p1=l1,*p2=l2;
            while(p1->next!=NULL&&p2->next!=NULL){
                int tmp=p1->val+p2->val+take;
                p1->val=tmp%10;
                take=tmp/10;
                p1=p1->next;
                p2=p2->next;
            }
            
            if(p1->next==NULL){
                int tmp=p1->val+p2->val+take;
                p1->val=tmp%10;
                take=tmp/10;
                if(p2->next==NULL)
                {
                    if(take==0)
                        return l1;
                    else
                        p1->next=new ListNode(take);
                }
                else{
                    if(take==0){
                        p1->next=p2->next;
                        return l1;
                    }
                    else{
                        p1->next=p2->next;
                        p2=p2->next;
                        while(p2->next!=NULL&&take!=0){
                            int tmp=p2->val+take;
                            p2->val=tmp%10;
                            take=tmp/10;
                            p2=p2->next;
                        }
                        if(p2->next==NULL){
                            if((take+p2->val)>=10){
                                
                                p2->next= new ListNode((take+p2->val)/10);
                                p2->val=(take+p2->val)%10;
                            }
                            else p2->val+=take;
                    }
                }
            }
            }
            else{
                int tmp=p1->val+p2->val+take;
                p1->val=tmp%10;
                take=tmp/10;
                p1=p1->next;
                while(p1->next!=NULL&&take!=0){
                    int tmp=p1->val+take;
                    p1->val=tmp%10;
                    take=tmp/10;
                    p1=p1->next;
                }
                if(p1->next==NULL){
                    if((take+p1->val)>=10){
                        
                        p1->next=new ListNode((take+p1->val)/10);
                        p1->val=(take+p1->val)%10;
                    }
                    else p1->val+=take;
                }
            }
            return l1;
            
            
        }
    };
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  • 原文地址:https://www.cnblogs.com/LUO77/p/5652077.html
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