Django学习笔记：为Model添加Action

|- Django版本：1.8

|- Python版本：3.4

models.py

 1 class Story(models.Model):

#编辑Story状态
    STATUS_CHOICES = (
        (1, '待编辑状态'),
        (2, '待批准状态'),
        (3, '已发布状态'),
        (4, '已存档'),
    )


    title = models.CharField(max_length=100, verbose_name=u'文章')
    slug = models.SlugField(verbose_name=u'简短标题')
    category =models.ForeignKey(Category, verbose_name=u'分类')
    owner = models.ForeignKey(User, verbose_name=u'发布者')
    status = models.IntegerField(choices=STATUS_CHOICES, default=1, verbose_name=u'发布状态')

    
    class Meta:
           ordering = ['modified','created']
           verbose_name_plural = verbose_name = '文章'


    def __str__(self):
        return self.title

admin.py

 1 class StoryAdmin(admin.ModelAdmin):
    list_display = ('title', 'owner', 'status', 'created', 'modified','read_times','top', 'id')
    search_fields = ('title', 'markdown_content')
    # 状态选择器
    list_filter = ('status', 'owner', 'created', 'modified',)
    prepopulated_fields = {'slug': ('title',)}
    actions = ['make_story_public']

    def make_story_public(self, request, queryset):
        # queryset参数为选中的Story对象
        rows_updated = queryset.update(status=3)
        message_bit = "%s 篇文章" % rows_updated
        self.message_user(request, "%s 已成功标记为已发布状态." % message_bit)
    make_story_public.short_description = u'修改选中文章为已发布状态'