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  • python基本数据类型——set

    一、集合的定义

    set集合,是一个无序且不重复的元素集合。

    集合对象是一组无序排列的可哈希的值,集合成员可以做字典中的键。集合支持用in和not in操作符检查成员,由len()内建函数得到集合的基数(大小), 用 for 循环迭代集合的成员。但是因为集合本身是无序的,不可以为集合创建索引或执行切片(slice)操作,也没有键(keys)可用来获取集合中元素的值。

    二、集合的创建

    s = set()
    s = {11,22,33,44}
    *注:创建空集合时,只能用set(),如果用第二种方法s={},创建的实际上是一个空字典。
    s = {}
    print(type(s))
    <class 'dict'>
    
    a=set('boy')
    b=set(['y', 'b', 'o','o'])
    c=set({"k1":'v1','k2':'v2'})
    d={'k1','k2','k2'}
    e={('k1', 'k2','k2')}
    print(a,type(a))
    print(b,type(b))
    print(c,type(c))
    print(d,type(d))
    print(e,type(e))
    执行结果如下:
    {'o', 'b', 'y'} <class 'set'>
    {'o', 'b', 'y'} <class 'set'>
    {'k1', 'k2'} <class 'set'>
    {'k1', 'k2'} <class 'set'>
    {('k1', 'k2', 'k2')} <class 'set'>

    三、集合的功能

      1 class set(object):
      2     """
      3     set() -> new empty set object
      4     set(iterable) -> new set object
      5      
      6     Build an unordered collection of unique elements.
      7     """
      8     def add(self, *args, **kwargs): # real signature unknown
      9         """
     10         Add an element to a set,添加元素
     11          
     12         This has no effect if the element is already present.
     13         """
     14         pass
     15  
     16     def clear(self, *args, **kwargs): # real signature unknown
     17         """ Remove all elements from this set. 清楚内容"""
     18         pass
     19  
     20     def copy(self, *args, **kwargs): # real signature unknown
     21         """ Return a shallow copy of a set. 浅拷贝  """
     22         pass
     23  
     24     def difference(self, *args, **kwargs): # real signature unknown
     25         """
     26         Return the difference of two or more sets as a new set. A中存在,B中不存在
     27          
     28         (i.e. all elements that are in this set but not the others.)
     29         """
     30         pass
     31  
     32     def difference_update(self, *args, **kwargs): # real signature unknown
     33         """ Remove all elements of another set from this set.  从当前集合中删除和B中相同的元素"""
     34         pass
     35  
     36     def discard(self, *args, **kwargs): # real signature unknown
     37         """
     38         Remove an element from a set if it is a member.
     39          
     40         If the element is not a member, do nothing. 移除指定元素,不存在不保错
     41         """
     42         pass
     43  
     44     def intersection(self, *args, **kwargs): # real signature unknown
     45         """
     46         Return the intersection of two sets as a new set. 交集
     47          
     48         (i.e. all elements that are in both sets.)
     49         """
     50         pass
     51  
     52     def intersection_update(self, *args, **kwargs): # real signature unknown
     53         """ Update a set with the intersection of itself and another.  取交集并更更新到A中 """
     54         pass
     55  
     56     def isdisjoint(self, *args, **kwargs): # real signature unknown
     57         """ Return True if two sets have a null intersection.  如果没有交集,返回True,否则返回False"""
     58         pass
     59  
     60     def issubset(self, *args, **kwargs): # real signature unknown
     61         """ Report whether another set contains this set.  是否是子序列"""
     62         pass
     63  
     64     def issuperset(self, *args, **kwargs): # real signature unknown
     65         """ Report whether this set contains another set. 是否是父序列"""
     66         pass
     67  
     68     def pop(self, *args, **kwargs): # real signature unknown
     69         """
     70         Remove and return an arbitrary set element.
     71         Raises KeyError if the set is empty. 移除元素
     72         """
     73         pass
     74  
     75     def remove(self, *args, **kwargs): # real signature unknown
     76         """
     77         Remove an element from a set; it must be a member.
     78          
     79         If the element is not a member, raise a KeyError. 移除指定元素,不存在保错
     80         """
     81         pass
     82  
     83     def symmetric_difference(self, *args, **kwargs): # real signature unknown
     84         """
     85         Return the symmetric difference of two sets as a new set.  对称交集
     86          
     87         (i.e. all elements that are in exactly one of the sets.)
     88         """
     89         pass
     90  
     91     def symmetric_difference_update(self, *args, **kwargs): # real signature unknown
     92         """ Update a set with the symmetric difference of itself and another. 对称交集,并更新到a中 """
     93         pass
     94  
     95     def union(self, *args, **kwargs): # real signature unknown
     96         """
     97         Return the union of sets as a new set.  并集
     98          
     99         (i.e. all elements that are in either set.)
    100         """
    101         pass
    102  
    103     def update(self, *args, **kwargs): # real signature unknown
    104         """ Update a set with the union of itself and others. 更新 """
    105         pass
    106 
    107 源码
    源码

    基本功能:

    • 增加(add, update)
    a=set('python')
    a.add('tina')
    print(a)
    b=set('python')
    b.update('tina')
    print(b)
    执行结果如下:
    {'tina', 'o', 'p', 'n', 't', 'y', 'h'}
    {'o', 'i', 'p', 'a', 'n', 't', 'y', 'h'}
    ##################
    由以上代码可以看出,add是单个元素的添加,而update是批量的添加。输出结果是无序的,并非添加到尾部。
    • 删除(remove,discard,pop)
    c={'p', 'i', 'h', 'n', 'o', 'y', 't'}
    c.remove('p')
    print(c)
    
    c={'p', 'i', 'h', 'n', 'o', 'y', 't'}
    c.discard('p')
    print(c)
    c={'p', 'i', 'h', 'n', 'o', 'y', 't'}
    c.pop()
    print(c)
    执行结果如下: {'i', 'h', 't', 'o', 'y', 'n'} 
    #####
    
    当执行c.remove('p','i')和c.discard('p','i')时,报错:TypeError: remove() takes exactly one argument (2 given),说明remove和discard删除元素时都只能一个一个的删,同add对应。
    #################################################################################
    remove,pop和discard的区别:
    discard删除指定元素,当指定元素不存在时,不报错;
    remove删除指定元素,但当指定元素不存在时,报错:KeyError。
    pop删除任意元素,并可将移除的元素赋值给一个变量,不能指定元素移除。

    set的特有功能:

    s1 = {0}
    s2 = {i % 2 for i in range(10)}
    s = set('hi')
    t = set(['h', 'e', 'l', 'l', 'o'])
    print(s.intersection(t), s & t)  # 交集
    print(s.union(t), s | t)   # 并集
    print(s.difference(t), s - t)  # 差集
    print(s.symmetric_difference(t), s ^ t) # 对称差集
    print(s1.issubset(s2), s1 <= s2) # 子集(被包含)
    print(s1.issuperset(s2), s1 >= s2)   # 父集(包含)
    
    执行结果如下:
    {'h'} {'h'}
    {'i', 'e', 'h', 'l', 'o'} {'i', 'e', 'h', 'l', 'o'}
    {'i'} {'i'}
    {'e', 'l', 'o', 'i'} {'e', 'l', 'o', 'i'}
    True True
    False False
    
    s = {11,22,33}
    t = {22,44}
    print(s.isdisjoint(t))#(disjoint脱节的,)即如果没有交集,返回True,否则返回False
    s.difference_update(t)#将差集覆盖到源集合,即从当前集合中删除和B中相同的元素
    print(s)
    执行结果如下:
    False
    {33, 11}
    
    s = {11,22,33}
    t = {22,44}
    s.intersection_update(t)#将交集覆盖到源集合
    print(s)
    执行结果如下:
    {22}
    
    s = {11,22,33}
    t = {22,44}
    s.symmetric_difference_update(t)#将对称差集覆盖到源集合
    print(s)
    执行结果如下:
    {33, 11, 44}

    四、练习题

    寻找差异:哪些需要删除?哪些需要新建?哪些需要更新?

    #!/usr/bin/python
    # -*- coding:utf-8 -*-
    old_dict = {
        "#1": {'hostname': 'c1', 'cpu_count': 2, 'mem_capicity': 80},
        "#2": {'hostname': 'c1', 'cpu_count': 2, 'mem_capicity': 80},
        "#3": {'hostname': 'c1', 'cpu_count': 2, 'mem_capicity': 80},
    }
    
    
    new_dict = {
        "#1": {'hostname': 'c1', 'cpu_count': 2, 'mem_capicity': 800},
        "#3": {'hostname': 'c1', 'cpu_count': 2, 'mem_capicity': 80},
        "#4": {'hostname': 'c2', 'cpu_count': 2, 'mem_capicity': 80},
    }
    new_set = set()
    old_set = set()
    for i in new_dict:
        new_set.add(i)
    for j in old_dict:
        old_set.add(j)
    new_add = new_set.difference(old_set)    #new_dict中有,old_dict中沒有
    old_del = old_set.difference(new_set)    #old_dict中有,new_dict中沒有
    update = new_set.intersection(old_set)    #old_dict和new_dict共同有的,需要把new_dict更新到old_dict中
    
    for k in new_add:
        old_dict[k] = new_dict[k]    #將new_dict中新增的內容添加到old_dict中
    for v in old_del:
        del old_dict[v]    #將old_dict中失效的內容刪除
    for m in update:
        old_dict[m] = new_dict[m]    #把new_dict更新到old_dict中
    
    print(old_dict)
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  • 原文地址:https://www.cnblogs.com/LiCheng-/p/6430708.html
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