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  • Scala入门系列(十一):模式匹配

    引言

    模式匹配是Scala中非常有特色,非常强大的一种功能。

    类似于Java中的switch case语法,但是模式匹配的功能要比它强大得多,switch只能对值进行匹配,但是Scala的模式匹配除了可以对值进行匹配之外,还可以对类型进行匹配、对Array和List的元素情况进行匹配、对case class进行匹配甚至对有值或没值(Option)进行匹配

    而且在Spark源码中也大量地使用了模式匹配功能。因此为了更好地编写Scala程序,并且更加通畅地看懂Spark源码,学好模式匹配是非常重要的。

    基础语法

    match case的语法如下:变量 match { case 值 => 代码}。如果值为下划线,则代表不满足以上所有情况下的默认情况如何处理。此外,match case中,只要一个case分支满足并处理了,就不会继续判断下一个case分支了。(这一点与java不同,java的switch case需要用break阻止)

    对变量值进行匹配

    // 案例:成绩评价
    def judgeGrade(grade: String) {
    grade match {
    case "A" => println("Excellent")
    case "B" => println("Good")
    case "C" => println("Just so so")
    case _ => println("you need work harder")
    }
    }
    judgeGrade: (grade: String)Unit
    scala> judgeGrade("E")
    you need work harder
    scala> judgeGrade("B")
    Good

    在模式匹配中使用if守卫

    // 案例:成绩评价(升级版)
    def judgeGrade(name: String, grade: String){
    grade match {
    case "A" => println("Excellent")
    case "B" => println("Good")
    case "C" => println("Just so so")
    case _ if name == "leo" => println(name + ", you are a good boy, come on")
    case _ => println("you need to work harder")
    }
    }
    judgeGrade: (name: String, grade: String)Unit
    scala> judgeGrade("leo", "E")
    leo, you are a good boy, come on
    scala> judgeGrade("sparks", "E")
    you need to work harder

    在模式匹配中进行变量赋值

    模式匹配中可以将默认情况即下划线替换为一个变量名,这样模式匹配语法就会将要匹配的值赋值给这个变量,从而可以在后面的处理语句中使用要匹配的值。

    // 案例:成绩评价(升级版)
    def judgeGrade(grade: String){
    grade match {
    case "A" => println("you got A grade, excellent!")
    case "B" => println("you got B grade, good")
    case "C" => println("you got C grade, so so")
    case badGrade => println("you got " + badGrade + "grade, i hope that you can get C next time")
    }
    }
    judgeGrade: (grade: String)Unit
    scala> judgeGrade("E")
    you got Egrade, i hope that you can get C next time
    scala> judgeGrade("F")
    you got Fgrade, i hope that you can get C next time

    类型匹配

    Scala的模式匹配强大之处就在于可以直接匹配类型而不仅仅是值,这也是Java中switch case绝对做不到的。

    匹配类型的语法为case 变量 : 类型 => 代码

    // 案例:异常处理
    import java.io._
    def processException(e: Exception){
    e match {
    case e1:IllegalArgumentException => println("you passed illegal argument, exception is : " +e1)
    case e2:IOException => println("you got an error while doing IO operation!" + e2)
    case _:Exception => println("cannot know which exception you have")
    }
    }
    processException: (e: Exception)Unit
    // 测试能否匹配类型
    scala> processException(new IllegalArgumentException("expect two arguments, but found only one"))
    you passed illegal argument, exception is : java.lang.IllegalArgumentException: expect two arguments
    , but found only one
    scala> processException(new ArrayIndexOutOfBoundsException("array is null."))
    cannot know which exception you have

    对Array和List的元素进行匹配

    对Array进行模式匹配,分别可以匹配带有指定元素的数组、带有指定个数的数组、以某元素打头的数组。

    def greeting(arr: Array[String]) {
    arr match {
    case Array("Leo") => println("Hi, Leo!")
    case Array(girl1,girl2,girl3) => println("Hi, girls, may I know you name? "+girl1+" "+girl2+" "+
    girl3)
    case Array("Leo", _*) => println("Hi, leo, please introduce your friends to me.")
    case _ => println("hey, who are you?")
    }
    }
    greeting: (arr: Array[String])Unit
    // 测试
    scala> greeting(Array("Leo"))
    Hi, Leo!
    scala> greeting(Array("jen", "Alice", "lory"))
    Hi, girls, may I know you name? jen Alice lory
    scala> greeting(Array("sparks"))
    hey, who are you?

      
    对List进行模式匹配,与Array类似,但是需要使用List特有的 :: 操作符。

    def greeting(list: List[String]){
    list match {
    case "Leo" :: Nil => println("Hi, Leo!")
    case girl1 :: girl2 :: girl3 ::Nil => println("Hi, girls, nice to meet you." + girl1 + " " + gir
    l2 + " " + girl3)
    case "Leo" :: tail => println("Hi, Leo, please introduce your friends to me.")
    case _ => println("hey, who are you?")
    }
    }
    greeting: (list: List[String])Unit
    // 测试
    scala> greeting(List("Leo"))
    Hi, Leo!
    scala> greeting(List("Marry", "Alice", "lory"))
    Hi, girls, nice to meet you.Marry Alice lory
    scala> greeting(List("Sparks"))
    hey, who are you?

    case class匹配

    Scala中提供了一种特殊的类,用case class进行声明,中文也可以称作样例类。case class其实有点类似于Java中的JavaBean的概念。即只定义field,并且由Scala编译时自动提供getter和setter方法,但是没有method

    case class的主构造函数接收的参数通常不需要使用val或var修饰,Scala自动就会使用val修饰(但是如果你自己使用var修饰,那么还是会按照var来定义)

    Scala自动为case class定义了伴生对象,也就是object,并且定义了apply()方法,该方法接收主构造函数中相同的参数,并返回case class对象。

    // 定义case class
    class Person
    case class Teacher(name: String, subject: String) extends Person
    case class Student(name: String, classroom: String) extends Person
    case class Worker(name: String) extends Person
    // 案例:学校门禁
    def judgeIdentify(p: Person) {
    p match {
    case Teacher(name, subject) => println("Teacher, name is " +name+ ",subject is " + subject)
    case Student(name, classroom) => println("Student, name is" + name + ", classroom is " + classro
    om)
    case _ => println("Illegal access, please go out of the school")
    }
    }
    defined class Person
    defined class Teacher
    defined class Student
    defined class Worker
    judgeIdentify: (p: Person)Unit
    // 测试匹配效果
    scala> val leo: Person = Student("leo", "class1")
    leo: Person = Student(leo,class1)
    scala> val tom: Person = Teacher("tom", "Math")
    tom: Person = Teacher(tom,Math)
    scala> val jack: Person = Worker("jack")
    jack: Person = Worker(jack)
    scala> judgeIdentify(leo)
    Student, name isleo, classroom is class1
    scala> judgeIdentify(tom)
    Teacher, name is tom,subject is Math
    scala> judgeIdentify(jack)
    Illegal access, please go out of the school

    Option匹配

    Scala中有一种特殊的类型,叫做Option。Option有两种值,一种是Some,表示有值,一种是None,表示没有值。

    Option通常会用于模式匹配中,用于判断某个变量是有值还是没有值,这比null来的更加简洁明了。

    Spark源码中大量地使用了Option,比如Some(a)、None这种语法。

    // 案例:成绩查询
    val grades = Map("Leo" -> "A", "Jack" -> "B", "Sparks" -> "C")
    def getGrade(name: String) {
    val grade = grades.get(name)
    grade match {
    case Some(grade) => println("your grade is " + grade)
    case None => println("Sorry, your grade information is not in the system")
    }
    }、
    grades: scala.collection.immutable.Map[String,String] = Map(Leo -> A, Jack -> B, Sparks -> C)
    getGrade: (name: String)Unit
    // 测试
    scala> getGrade("Leo")
    your grade is A
    scala> getGrade("Sparks")
    your grade is C
    scala> getGrade("haha")
    Sorry, your grade information is not in the system
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  • 原文地址:https://www.cnblogs.com/LiCheng-/p/8060059.html
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