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  • 设计url 通过分发的方式 Xadmin_demo

    urlpatterns = [
    url(r'^Xadmin/',([
              url(r'^add/$', views.add)
              url(r'^delete/$', views.delete)
              ], None,None)),
    这样就完成了一级分发

    然后进行自行设计url
    需求 3张表,增删改查, 12个url

    127.0.0.1:8000/Xadmin/app01/add/
    127.0.0.1:8000/Xadmin/app01/delete/


    在urls.py编辑

    def list_view(request):
    return HttpResponse('userindex')
    def add_view(request):
    return HttpResponse('user_add')
    def change_view(request, id):
    return HttpResponse('user_change')
    def delete_view(request, id):
    return HttpResponse('user_delete')

    def has_urls():
    temp = []
    temp.append(url(r'^$',list_view))
    temp.append(url(r'^add/$',add_view))
    temp.append(url(r'^(d+)/change/$',change_view))
    temp.append(url(r'^(d+)/delete/$',delete_view))
    print(temp)
    return temp
    def get_urls():
    print(admin.site._registry)
    temp = []
    for model,admin_class_obj in admin.site._registry.items():
    app_name = model._meta.app_label
    model_name = model._meta.model_name
    print(app_name,model_name)
    temp.append(url(r'^{0}/{1}/'.format(app_name,model_name),(has_urls(), None,None)),)
    return temp
    urlpatterns = [
    path('admin/', admin.site.urls),
    url(r'^Xadmin/',(get_urls(), None,None)),]

    settings.py
    设置
    INSTALLED_APPS = [
    'app01.apps.App01Config',

    'app02.apps.App02Config',
    ]

    app01项目下的admin.py
    from django.contrib import admin
    from app01 import models
    # Register your models here.
    admin.site.register(models.Book)
    admin.site.register(models.Publish)

    app01项目下的models.py


    app02项目下的admin.py
    from django.contrib import admin
    from app02 import models
    # Register your models here.
    admin.site.register(models.Order)

    app01项目下的models.py
    from django.db import models
    class Order(models.Model):
    title = models.CharField(max_length=32)
    def __str__(self):
    return self.title



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  • 原文地址:https://www.cnblogs.com/Liang-jc/p/9568627.html
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