A1005

输出输入的n位整数的每一位之和的英文，注意一下输出的数组嵌套。

#include<cstdio>
#include<iostream>
using namespace std;
int main(){
    string num[10]={"zero","one","two","three","four","five","six","seven","eight","nine"};
    string input;
    cin>>input;
    long long sum=0,dig[1000];
    int len=input.length();
    for(int i=0;i<len;i++) sum+=input[i]-'0';
    int con=0;
    while(sum!=0){
        dig[con]=sum%10;
        sum=sum/10;
        con+=1;
    }
    cout<<num[dig[con-1]];
    for(int i=con-2;i>=0;i--){
        cout<<' '<<num[dig[i]];
    }
    return 0;
}