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  • BUUCTF--[GUET-CTF2019]re

    测试文件:https://www.lanzous.com/ib3elba

    脱壳

    获取信息

    • 64位文件
    • upx加壳

    代码分析

     1 __int64 sub_400E28()
     2 {
     3   const char *v0; // rdi
     4   __int64 result; // rax
     5   __int64 v2; // rdx
     6   unsigned __int64 v3; // rt1
     7   __int64 v4; // [rsp+0h] [rbp-30h]
     8   __int64 v5; // [rsp+8h] [rbp-28h]
     9   __int64 v6; // [rsp+10h] [rbp-20h]
    10   __int64 v7; // [rsp+18h] [rbp-18h]
    11   unsigned __int64 v8; // [rsp+28h] [rbp-8h]
    12 
    13   v8 = __readfsqword(0x28u);
    14   v4 = 0LL;
    15   v5 = 0LL;
    16   v6 = 0LL;
    17   v7 = 0LL;
    18   sub_40F950((__int64)"input your flag:", 0LL, 0LL, 0LL, 0LL);
    19   sub_40FA80((__int64)"%s", &v4);
    20   if ( (unsigned int)sub_4009AE(&v4, &v4) )
    21   {
    22     v0 = "Correct!";
    23     sub_410350("Correct!");
    24   }
    25   else
    26   {
    27     v0 = "Wrong!";
    28     sub_410350("Wrong!");
    29   }
    30   result = 0LL;
    31   v3 = __readfsqword(0x28u);
    32   v2 = v3 ^ v8;
    33   if ( v3 != v8 )
    34     sub_443550(v0, &v4, v2);
    35   return result;
    36 }

    打开关键函数sub_4009AE

    _BOOL8 __fastcall sub_4009AE(char *a1)
    {
      if ( 1629056 * *a1 != 166163712 )
        return 0LL;
      if ( 6771600 * a1[1] != 731332800 )
        return 0LL;
      if ( 3682944 * a1[2] != 357245568 )
        return 0LL;
      if ( 10431000 * a1[3] != 1074393000 )
        return 0LL;
      if ( 3977328 * a1[4] != 489211344 )
        return 0LL;
      if ( 5138336 * a1[5] != 518971936 )
        return 0LL;
      if ( 7532250 * a1[7] != 406741500 )
        return 0LL;
      if ( 5551632 * a1[8] != 294236496 )
        return 0LL;
      if ( 3409728 * a1[9] != 177305856 )
        return 0LL;
      if ( 13013670 * a1[10] != 650683500 )
        return 0LL;
      if ( 6088797 * a1[11] != 298351053 )
        return 0LL;
      if ( 7884663 * a1[12] != 386348487 )
        return 0LL;
      if ( 8944053 * a1[13] != 438258597 )
        return 0LL;
      if ( 5198490 * a1[14] != 249527520 )
        return 0LL;
      if ( 4544518 * a1[15] != 445362764 )
        return 0LL;
      if ( 3645600 * a1[17] != 174988800 )
        return 0LL;
      if ( 10115280 * a1[16] != 981182160 )
        return 0LL;
      if ( 9667504 * a1[18] != 493042704 )
        return 0LL;
      if ( 5364450 * a1[19] != 257493600 )
        return 0LL;
      if ( 13464540 * a1[20] != 767478780 )
        return 0LL;
      if ( 5488432 * a1[21] != 312840624 )
        return 0LL;
      if ( 14479500 * a1[22] != 1404511500 )
        return 0LL;
      if ( 6451830 * a1[23] != 316139670 )
        return 0LL;
      if ( 6252576 * a1[24] != 619005024 )
        return 0LL;
      if ( 7763364 * a1[25] != 372641472 )
        return 0LL;
      if ( 7327320 * a1[26] != 373693320 )
        return 0LL;
      if ( 8741520 * a1[27] != 498266640 )
        return 0LL;
      if ( 8871876 * a1[28] != 452465676 )
        return 0LL;
      if ( 4086720 * a1[29] != 208422720 )
        return 0LL;
      if ( 9374400 * a1[30] == 515592000 )
        return 5759124 * a1[31] == 719890500;
      return 0LL;
    }

    a1就是我们输入的v4,反向除就行

    脚本

    # -*- coding:utf-8 -*-
    
    a1 = chr(166163712 // 1629056)
    a2 = chr(731332800 // 6771600)
    a3 = chr(357245568 // 3682944)
    a4 = chr(1074393000 // 10431000)
    a5 = chr(489211344 // 3977328)
    a6 = chr(518971936 // 5138336)
    a8 = chr(406741500 // 7532250)
    a9 = chr(294236496 // 5551632)
    a10 = chr(177305856 // 3409728)
    a11 = chr(650683500 // 13013670)
    a12 = chr(298351053 // 6088797)
    a13 = chr(386348487 // 7884663)
    a14 = chr(438258597 // 8944053)
    a15 = chr(249527520 // 5198490)
    a16 = chr(445362764 // 4544518)
    a17 = chr(981182160 // 10115280)
    a18 = chr(174988800 // 3645600)
    a19 = chr(493042704 // 9667504)
    a20 = chr(257493600 // 5364450)
    a21 = chr(767478780 // 13464540)
    a22 = chr(312840624 // 5488432)
    a23 = chr(1404511500 // 14479500)
    a24 = chr(316139670 // 6451830)
    a25 = chr(619005024 // 6252576)
    a26 = chr(372641472 // 7763364)
    a27 = chr(373693320 // 7327320)
    a28 = chr(498266640 // 8741520)
    a29 = chr(452465676 // 8871876)
    a30 = chr(208422720 // 4086720)
    a31 = chr(515592000 // 9374400)
    a32 = chr(719890500 // 5759124)
    
    print (a1,a2,a3,a4,a5,a6,a8,a9,a10,a11,a12,a13,a14,a15,a16,a17,a18,a19,a20,a21,a22,a23,a24,a25,a26,a27,a28,a29,a30,a31,a32)

    这上面缺了一位,只能爆破得到a7=1

    get flag!

    flag{e165421110ba03099a1c039337}

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  • 原文地址:https://www.cnblogs.com/Mayfly-nymph/p/12655622.html
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