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  • bzoj4003

    用左偏树不断向上维护仍在[浴血奋战的]骑士攻击力,不断维护tag维护即可

    #include<cstdio>
    #include<cctype>
    #define ml(x) tr[x].ml
    #define ad(x) tr[x].ad
    #define ls(x) tr[x].l
    #define rs(x) tr[x].r
    #define vl(x) tr[x].val
    inline char nc(){
        static char buf[100000],*p1=buf,*p2=buf;
        return p1==p2&&(p2=(p1=buf)+fread(buf,1,100000,stdin),p1==p2)?EOF:*p1++;
    }
    #define M 500000
    typedef long long ll;
    const int N=3e5+5;
    template<class T>inline void read(T &x){
    	char ch=nc();x=0;ll f=1;
    	for(;!isdigit(ch);ch=nc())if(ch=='-')f=-1;
    	for(;isdigit(ch);ch=nc())x=(x<<1)+(x<<3)+ch-'0';
    	x*=f;
    }
    int a[N];
    int n,m,cnt,c[N],rt[N],dep[N],head[N],nex[N],to[N],s[N],ans[N];
    ll h[N],v[N];
    struct data{int dis,l,r;ll ml,ad,val;}tr[N];
    inline void swap(int &x,int &y){int tmp=x;x=y,y=tmp;}
    inline void addedge(int u,int v){
    	nex[++cnt]=head[u],head[u]=cnt,to[cnt]=v;
    }
    inline void pushdown(int x){
    	if(ls(x))vl(ls(x))=vl(ls(x))*ml(x)+ad(x),ml(ls(x))*=ml(x),ad(ls(x))=ad(ls(x))*ml(x)+ad(x);
    	if(rs(x))vl(rs(x))=vl(rs(x))*ml(x)+ad(x),ml(rs(x))*=ml(x),ad(rs(x))=ad(rs(x))*ml(x)+ad(x);
    	ml(x)=1,ad(x)=0;
    }
    inline int merge(int x,int y){
    	if(!x||!y)return x+y;
    	pushdown(x),pushdown(y);
    	if(vl(x)>vl(y))swap(x,y);
    	rs(x)=merge(rs(x),y);
    	if(tr[ls(x)].dis<tr[rs(x)].dis)swap(ls(x),rs(x));
    	tr[x].dis=tr[ls(x)].dis+1;
    	return x;
    }
    inline void dfs(int x){
    	for(int t,i=head[x];i;i=nex[i]){
    		t=to[i],dep[t]=dep[x]+1,dfs(t);
    		if(!a[t])vl(rt[t])+=v[t],ad(rt[t])+=v[t];
    		else vl(rt[t])*=v[t],ad(rt[t])*=v[t],ml(rt[t])*=v[t];
    		rt[x]=merge(rt[x],rt[t]);
    	}
    	while(rt[x]&&vl(rt[x])<h[x])ans[rt[x]]=x,pushdown(rt[x]),s[x]++,rt[x]=merge(ls(rt[x]),rs(rt[x]));
    }
    inline void write(int x){
    	if(x<10)putchar(x+'0');
    	else write(x/10),putchar((x%10)+'0');
    }
    int main(){
    	read(n),read(m),dep[0]=-1;;
    	for(int i=1;i<=n;i++)read(h[i]);
    	for(int x,i=2;i<=n;i++)read(x),addedge(x,i),read(a[i]),read(v[i]);
    	for(int i=1;i<=m;i++){
    		read(tr[i].val),read(c[i]),tr[i].ml=1;
    		rt[c[i]]=merge(rt[c[i]],i);
    	}
    	dfs(1);
    	for(int i=1;i<=n;i++)write(s[i]),puts("");
    	for(int i=1;i<=m;i++)write(dep[c[i]]-dep[ans[i]]),puts("");
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/MikuKnight/p/9863073.html
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