HDU 1711 Number Sequence(模板题)
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#include<stdio.h> #include<string> const int maxn=1e6+10; const int maxm=1e4+10; int t,n,m,s[maxn],p[maxn]; int next[maxm]; void GetNext() { int plen=0; int slen=-1; next[0]=-1; while(plen<m) { if(slen==-1||p[plen]==p[slen]) { plen++;slen++; if(p[plen]!=p[slen])next[plen]=slen; else next[plen]=next[slen]; } else slen=next[slen]; } } int kmp() { int plen=0; int slen=0; while(plen<m&&slen<n) { if(plen==-1||p[plen]==s[slen]) { plen++;slen++; } else plen=next[plen]; } if(plen==m) return slen-plen+1; else return -1; } int main() { scanf("%d",&t); while(t--) { scanf("%d%d",&n,&m); for(int i=0;i<n;i++)scanf("%d",&s[i]); for(int i=0;i<m;i++)scanf("%d",&p[i]); GetNext(); printf("%d ",kmp()); } return 0; }
HDU 2087 剪花布条
求一个串在另一个串中的出现次数,KMP模板题
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#include<iostream> #include<string> using namespace std; string s,p; int plen,slen,Next[1010]; void GetNext() { int j=0; int k=-1; Next[0]=-1; while(j<plen) { if(k==-1||p[j]==p[k]) { j++;k++; if(p[j]!=p[k])Next[j]=k; else Next[j]=Next[k]; } else k=Next[k]; } } int kmp() { int j=0; int i=0; int count=0; while(j<plen&&i<slen) { if(j==-1||p[j]==s[i]) { j++;i++; } else j=Next[j]; if(j==plen) { j=0; count++; } } return count; } int main() { while(cin>>s&&s[0]!='#') { cin>>p; plen=p.size(); slen=s.size(); GetNext(); printf("%d ",kmp()); } return 0; }
HDU 2594 Simpsons’ Hidden Talents (next函数应用)
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#include<iostream> #include<string.h> using namespace std; const int maxn=5e5+10; char s1[maxn],s2[maxn]; int Next[maxn],len1,len2,ans; void GetNext() { int k=-1; int j=0; Next[0]=-1; while(j<len1+len2) { if(k==-1||s1[j]==s1[k]) { j++;k++;Next[j]=k; } else k=Next[k]; } } int main() { while(~scanf("%s%s",s1,s2)) { len1=strlen(s1); len2=strlen(s2); strcat(s1,s2); GetNext(); ans=Next[len1+len2]; while(ans>len1||ans>len2)ans=Next[ans]; if(ans){ for(int i=0;i<ans;i++)printf("%c",s1[i]);printf(" %d",ans);printf(" "); } else printf("%d ",ans); } return 0; }