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  • 【luogu P1462 通往奥格瑞玛的道路】 题解

    题目链接:https://www.luogu.org/problemnew/show/P1462
    记住HP=0也叫死。

    #include <queue>
    #include <cstdio>
    #include <cstring>
    #include <iostream>
    #include <algorithm>
    using namespace std;
    const int maxn = 5000001;
    const int inf = 0x7f;
    long long n, m, s, dis[maxn], hp, f[maxn], u[maxn];
    bool vis[maxn<<2];
    struct edge{
        int to, from, len, next;
    }e[maxn];
    int head[maxn], cnt;
    void add(int u, int v, int w)
    {
        e[++cnt].from = u;
        e[cnt].len = w;
        e[cnt].to = v;
        e[cnt].next = head[u];
        head[u] = cnt;
    }
    int SPFA(int top)
    {
        memset(dis,inf,sizeof(dis));
        memset(vis,0,sizeof(vis));
        queue<int> q;
        vis[1] = 1;
        dis[1] = 0;
        q.push(1);
        while(!q.empty())
        {
            int now = q.front(); q.pop();
            vis[now] = 0;
            for(int i = head[now]; i != -1; i = e[i].next)
            {
                if(dis[e[i].to] > dis[now]+e[i].len && f[e[i].to]<=top)
                {
                    dis[e[i].to] = dis[now]+e[i].len;
                    if(vis[e[i].to] == 0)
                    {
                        vis[e[i].to] = 1;
                        q.push(e[i].to);
                    }
                }
            }
        }
        if(dis[n] < hp)
        return true;
        else
        return false;
    }
    int main()
    {
        //freopen("in.txt","r",stdin);
        //freopen("out.txt","w",stdout);
        memset(head,-1,sizeof(head));
        scanf("%d%d%d",&n,&m,&hp);
        for(int i = 1; i <= n; i++)
        {
            scanf("%d",&f[i]);
            u[i] = f[i];
        }
        for(int i = 1; i <= m; i++)
        {
            int u, v, w;
            scanf("%d%d%d",&u,&v,&w);
            add(u,v,w);
            add(v,u,w);
        }
        if(SPFA(0x7fffffff) == false)
        {
            printf("AFK
    ");
            return 0;
        }
        sort(u+1,u+1+n);
        int l = 1, r = n, mid, ans = 0; 
        while(l <= r)
        {
            mid = (l+r)/2;
            if(SPFA(u[mid]) == true)
            {
                ans = u[mid];
                r = mid-1;
            }
            else
            l = mid+1;
        }
        printf("%d
    ",ans);
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/MisakaAzusa/p/9231388.html
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