zoukankan      html  css  js  c++  java
  • 【luogu P1608 路径统计】 题解

    题目链接:https://www.luogu.org/problemnew/show/P1608

    补上一发最短路计数!

    感谢王强qwqqqq @Lance1ot

    #include <queue>
    #include <cstdio>
    #include <cstring>
    #include <iostream>
    #include <algorithm>
    using namespace std;
    const int maxn = 200010;
    int dis[maxn], ans[maxn], n, m, k, used[2010][2010];
    bool vis[maxn];
    struct edge{
        int next, to, len;
    }e[maxn<<2];
    int head[maxn], cnt;
    queue<int> q;
    void add(int u, int v, int w)
    {
        e[++cnt].len = w;
        e[cnt].next = head[u];
        e[cnt].to = v;
        head[u] = cnt;
    }
    void SPFA()
    {
        while(!q.empty())
        {
            int now = q.front(); q.pop();
            vis[now] = 0;
            if(now == n) continue;
            for(int i = head[now]; i != -1; i = e[i].next)
            {
                if(dis[e[i].to] == dis[now] + e[i].len)
                {
                    ans[e[i].to] = (ans[e[i].to] + ans[now]);
                    if(!vis[e[i].to])
                    {
                        q.push(e[i].to);
                        vis[e[i].to] = 1;
                    }
                }
                if(dis[e[i].to] > dis[now] + e[i].len)
                {
                    dis[e[i].to] = dis[now] + e[i].len;
                    ans[e[i].to] = ans[now];
                    if(!vis[e[i].to])
                    {
                        q.push(e[i].to);
                        vis[e[i].to] = 1;
                    }
                }
            }
            ans[now]=0;
        }
    }
    int main()
    {
            memset(head, -1, sizeof(head));
            memset(dis, 127, sizeof(dis));
            memset(used, 127, sizeof(used));
            while(!q.empty()) q.pop();
            scanf("%d%d",&n,&m);
            for(int i = 1; i <= m; i++)
            {
                int u, v, w;
                scanf("%d%d%d",&u,&v,&w);
                if(used[u][v] > w)
                {
                    add(u, v, w);
                    used[u][v] = w;
                }
            }
            dis[1] = 0;
            vis[1] = 1;
            ans[1] = 1;
            q.push(1);
            SPFA();
            if(dis[n] >= 2139062143) {printf("No answer
    "); return 0;}
            printf("%d %d
    ",dis[n], ans[n]);
    }
    
  • 相关阅读:
    移动端Rem布局注意事项
    手动添加kdump
    Linux 添加新磁盘,在线扩充空间
    virtualbox linux虚拟机相关
    CentOS7 重置root密码
    putty无密码登陆
    sublime text3 安装插件
    jsp常用代码
    jq鼠标移入移除
    ajax请求超时解决方案
  • 原文地址:https://www.cnblogs.com/MisakaAzusa/p/9818718.html
Copyright © 2011-2022 走看看