水题 给出n个数 排序后判断它们是否在10~13内 并且最小的数要为1 且至少两个数要为1 还要满足相邻两数之差小于等于2
AC代码：
1 #include<bits/stdc++.h> 2 using namespace std; 3 typedef long long ll; 4 typedef unsigned long long ull; 5 6 namespace io { 7 const int SIZE = 1e7 + 10; 8 char inbuff[SIZE]; 9 char *l, *r; 10 inline void init() { 11 l = inbuff; 12 r = inbuff + fread(inbuff, 1, SIZE, stdin); 13 } 14 inline char gc() { 15 if (l == r) init(); 16 return (l != r) ? *(l++) : EOF; 17 } 18 void read(int &x) { 19 x = 0; char ch = gc(); 20 while(!isdigit(ch)) ch = gc(); 21 while(isdigit(ch)) x = x * 10 + ch - '0', ch = gc(); 22 } 23 } using io::read; 24 25 int main(){ 26 int t; 27 scanf("%d", &t); 28 int n; 29 int s[105]; 30 bool flag; 31 while (t--){ 32 scanf("%d", &n); 33 memset(s, 0, sizeof(s)); 34 flag = true; 35 for (int i = 1; i <= n; i++) scanf("%d", &s[i]); 36 sort(s + 1, s + n + 1); 37 if (n < 10 || n > 13) flag = false; 38 if (s[1] != 1 || s[2] != 1) flag = false; 39 for (int i = 3; i < n; i++){ 40 if (s[i] - s[i - 1] > 2){ 41 flag = false; 42 break; 43 } 44 } 45 if (flag) cout<<"Yes"<<endl; 46 else cout<<"No"<<endl; 47 } 48 return 0; 49 }