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  • 【模板】点分治

    点分治

    POJ-1741

    #include <cstdio>
    #include <algorithm>
    using namespace std;
    const int N = 10010;
    const int INF = 0x3f3f3f3f;
    
    int n, k, ans;
    
    int head[N], nxt[2 * N], to[2 * N], w[2 * N], tot; //链式前向星
    void add_edge(int x, int y, int z) {
        nxt[++tot] = head[x];
        to[tot] = y;
        w[tot] = z;
        head[x] = tot;
    }
    
    bool vis[N];
    int Root, Tsiz, siz[N], mx[N];
    int arr[N], cnt;
    
    void init() {
        tot = ans = 0;
        for (int i = 0; i < N; i++) vis[i] = 0, head[i] = -1;
        Tsiz = n; mx[0] = INF; //最大子树节点数mx[0]初始化为INF
    }
    
    void GetRoot(int u, int fa) { //寻找树的重心
        siz[u] = 1; mx[u] = 0;
        for (int i = head[u]; ~i; i = nxt[i]) {
            if (to[i] != fa && !vis[to[i]]) {
                GetRoot(to[i], u);
                siz[u] += siz[to[i]];
                mx[u] = max(mx[u], siz[to[i]]);
            }
            mx[u] = max(mx[u], Tsiz - siz[u]);
            if (mx[Root] > mx[u]) Root = u;
        }
    }
    
    void GetDis(int u, int D, int fa) { //统计路径长度
        arr[++cnt] = D;
        for (int i = head[u]; ~i; i = nxt[i]) {
            if (to[i] != fa && !vis[to[i]])
                GetDis(to[i], D + w[i], u);
        }
    }
    
    int calc(int u, int D) {
        cnt = 0;
        GetDis(u, D, 0);
        int l = 1, r = cnt, sum = 0;
        sort(arr + 1, arr + 1 + cnt);
        for (;;++l) {
            while (r && arr[l] + arr[r] > k) --r;
            if (r < l) break;
            sum += r - l + 1;
        }
        return sum;
    }
    
    void DAC(int u) { //分治,u为当前树的重心
        ans += calc(u, 0); //加上当前点的答案
        vis[u] = 1;
        for (int i = head[u]; ~i; i = nxt[i]) {
            if (!vis[to[i]]) {
                ans -= calc(to[i], w[i]); //容斥原理
                Root = 0, Tsiz = siz[to[i]];
                GetRoot(to[i], 0); //得到子树的重心
                DAC(Root); //递归求解子树
            }
        }
    } //此法时间复杂度不会退化
    
    int main() {
        while (~scanf("%d %d", &n, &k) && n && k) {
            init();
            for (int i = 1; i < n; i++) {
                int x, y, z; scanf("%d %d %d", &x, &y, &z);
                add_edge(x, y, z); add_edge(y, x, z);
            }
            GetRoot(1, 0);
            DAC(Root);
            printf("%d
    ", ans - n); //去除(u, u)点对
        }
        return 0;
    }
    

    luogu_P3806

    #include <cstdio>
    #include <algorithm>
    #include <cstring>
    using namespace std;
    const int N = 10010; 
    const int INF = 0x3f3f3f3f; 
    
    int n, m;
    int query[N];
    bool vis[N], ok[N];
    int e_cnt, head[N], mx[N], sz[N], Root, cnt, a[N], b[N], d[N];
    /* 记当前分治的根为Root
    a[]记录从Root能到的点
    d[]记录a_i到Root的距离
    b[]记录a_i属于Root的哪一个子树(当b[a[i]] == b[a[j]]时,说明a_i与a_j属于Root的同一颗子树
    */
    struct Edge
    {
        int to, nxt, w;
    }edge[N << 1];
    
    void add_edge(int x, int y, int z) {
        edge[++e_cnt].nxt = head[x];
        edge[e_cnt].to = y;
        edge[e_cnt].w = z;
        head[x] = e_cnt;
    }
    
    void getRoot(int u, int fa, int total) {
        sz[u] = 1, mx[u] = 0;
        for (int i = head[u]; ~i; i = edge[i].nxt) {
            int v = edge[i].to;
            if (v == fa || vis[v]) continue;
            getRoot(v, u, total);
            sz[u] += sz[v];
            mx[u] = max(mx[u], sz[v]);
        }
        mx[u] = max(mx[u], total - sz[u]);
        if (mx[u] < mx[Root]) Root = u;
    }
    
    void getDis(int u, int fa, int dis, int from) {
        a[++cnt] = u;
        d[u] = dis;
        b[u] = from;
        for (int i = head[u]; ~i; i = edge[i].nxt) {
            int v = edge[i].to;
            if (v == fa || vis[v]) continue;
            getDis(v, u, dis + edge[i].w, from);
        }
    }
    
    bool cmp(int x, int y) { return d[x] < d[y]; }
    
    void calc(int u) {
        cnt = 0;
        a[++cnt] = u;
        d[u] = 0;
        b[u] = u;
        for (int i = head[u]; ~i; i = edge[i].nxt) {
            int v = edge[i].to;
            if (vis[v]) continue;
            getDis(v, u, edge[i].w, v);
        }
        sort(a + 1, a + 1 + cnt, cmp);
        for (int i = 1; i <= m; i++) {
            int l = 1, r = cnt;
            if (ok[i]) continue;
            while (l < r) {
                if (d[a[l]] + d[a[r]] > query[i]) r--;
                else if (d[a[l]] + d[a[r]] < query[i]) l++;
                else if (b[a[l]] == b[a[r]]) {
                    if (d[a[r]] == d[a[r - 1]]) r--;
                    else l++;
                }
                else { ok[i] = 1; break; }
            }
        }
    }
    
    void DAC(int u) {
        vis[u] = 1;
        calc(u);
        for (int i = head[u]; ~i; i = edge[i].nxt) {
            int v = edge[i].to;
            if (vis[v]) continue;
            Root = 0;
            getRoot(v, 0, sz[v]);
            DAC(Root);
        }
    }
    
    int main() {
        memset(head, -1, sizeof(head));
        scanf("%d %d", &n, &m);
        for (int i = 1; i < n; i++) {
            int x, y, z; scanf("%d %d %d", &x, &y, &z);
            add_edge(x, y, z); add_edge(y, x, z);
        }
        for (int i = 1; i <= m; i++) {
            scanf("%d", &query[i]);
            if (!query[i]) ok[i] = 1;
        }
        mx[0] = INF;
        getRoot(1, 0, n);
        DAC(Root);
        for (int i = 1; i <= m; i++) {
            if (ok[i]) printf("AYE
    ");
            else printf("NAY
    ");
        }
    }
    
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  • 原文地址:https://www.cnblogs.com/Nepenthe8/p/13568516.html
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