zoukankan      html  css  js  c++  java
  • POJ2752(KMP)

    Seek the Name, Seek the Fame

    Time Limit: 2000MS   Memory Limit: 65536K
    Total Submissions: 17175   Accepted: 8776

    Description

    The little cat is so famous, that many couples tramp over hill and dale to Byteland, and asked the little cat to give names to their newly-born babies. They seek the name, and at the same time seek the fame. In order to escape from such boring job, the innovative little cat works out an easy but fantastic algorithm: 

    Step1. Connect the father's name and the mother's name, to a new string S. 
    Step2. Find a proper prefix-suffix string of S (which is not only the prefix, but also the suffix of S). 

    Example: Father='ala', Mother='la', we have S = 'ala'+'la' = 'alala'. Potential prefix-suffix strings of S are {'a', 'ala', 'alala'}. Given the string S, could you help the little cat to write a program to calculate the length of possible prefix-suffix strings of S? (He might thank you by giving your baby a name:) 

    Input

    The input contains a number of test cases. Each test case occupies a single line that contains the string S described above. 

    Restrictions: Only lowercase letters may appear in the input. 1 <= Length of S <= 400000. 

    Output

    For each test case, output a single line with integer numbers in increasing order, denoting the possible length of the new baby's name.

    Sample Input

    ababcababababcabab
    aaaaa
    

    Sample Output

    2 4 9 18
    1 2 3 4 5

     1 //2016.8.17
     2 #include<iostream>
     3 #include<cstdio>
     4 #include<cstring>
     5 
     6 using namespace std;
     7 
     8 const int N = 400005;
     9 char s[N];
    10 int tot, ans[N], nex[N];
    11 
    12 void getNext(int n)
    13 {
    14     nex[0] = -1;
    15     for(int i = 0, fail = -1; i < n;)
    16     {
    17         if(fail==-1||s[i]==s[fail])
    18         {
    19             i++, fail++;
    20             nex[i] = fail;
    21         }else fail = nex[fail];
    22     }
    23 }
    24 
    25 int main()
    26 {
    27     while(scanf("%s", s)!=EOF)
    28     {
    29         int n = strlen(s);
    30         getNext(n);
    31         for(int i = 0; i < n; i++)
    32               cout<<nex[i]<<" ";
    33         cout<<endl;
    34         tot = 0;
    35         int p = nex[n-1];
    36         while(p!=-1)
    37         {
    38             if(s[p] == s[n-1])
    39               ans[tot++] = p+1;
    40             p = nex[p];
    41         }
    42         for(int i = tot-1; i >= 0; i--)
    43               printf("%d ", ans[i]);
    44         printf("%d
    ", n);
    45     }
    46 
    47     return 0;
    48 }
  • 相关阅读:
    git使用教程2-更新github上代码
    git使用教程-本地代码上传到github
    【Mac系统 + Git】之上传项目代码到github上以及删除某个文件夹
    【Mac + Appium + Python3.6学习(五)】之常用的Android自动化测试API总结
    【Mac + Python + Selenium】之PyCharm配置Selenium自动化
    appium自动化常用API
    【Mac + Appium + Python3.6学习(四)】之常用的IOS自动化测试API总结
    ubuntu指令大全
    Win10上安装双系统(win10+ubuntu)
    C语言共用体的作用
  • 原文地址:https://www.cnblogs.com/Penn000/p/5780098.html
Copyright © 2011-2022 走看看