PAT Basic Level 1027

AC代码

#include <stdio.h>
int main ()
{
    int amount;
    char pattern;
    scanf("%d %c",&amount,&pattern);
    int endNum = 1;
    int lineNum = 0;
    
    while(((1 + (2 *lineNum - 1)) * lineNum) / 2 * 2 - 1 < amount)
    {
        lineNum++;
    }
    if(((1 + (2 *lineNum - 1)) * lineNum) / 2 * 2 - 1 != amount)
    lineNum--;
    endNum = lineNum * 2 -1;
    int remain = 0;
    remain = amount - ((1 + (lineNum * 2 -1)) * lineNum / 2 * 2 -1);
    int i;
    int j;
    int p;  //控制空格 
    for(j = 0 ; j < lineNum ; j++)
    { 
        for(p = j;p > 0 ;p--)
        {
            printf(" ");
        }
        for(i = 0;i < (lineNum * 2 - 1) - (j * 2);i++)
        {
            printf("%c",pattern);
        }
        printf("
");    
    }
    for(j = 0;j < lineNum - 1;j++)
    {
        for(p = 0;p < lineNum - 2 - j;p++)
        {
            printf(" ");
        }
        for(i = 0;i < 3 + j * 2;i++)
        {
            printf("%c",pattern);
        }
        printf("
"); 
    } 
    printf("%d",remain);
    
    return 0 ;
 }