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  • [PAT] 1027 Colors in Mars (20 分) Java

    People in Mars represent the colors in their computers in a similar way as the Earth people. That is, a color is represented by a 6-digit number, where the first 2 digits are for Red, the middle 2 digits for Green, and the last 2 digits for Blue. The only difference is that they use radix 13 (0-9 and A-C) instead of 16. Now given a color in three decimal numbers (each between 0 and 168), you are supposed to output their Mars RGB values.

    Input Specification:

    Each input file contains one test case which occupies a line containing the three decimal color values.

    Output Specification:

    For each test case you should output the Mars RGB value in the following format: first output #, then followed by a 6-digit number where all the English characters must be upper-cased. If a single color is only 1-digit long, you must print a 0 to its left.

    Sample Input:

    15 43 71
    

    Sample Output:

    #123456



     1 package pattest;
     2 
     3 import java.io.BufferedReader;
     4 import java.io.IOException;
     5 import java.io.InputStreamReader;
     6 
     7 /**
     8  * @Auther: Xingzheng Wang
     9  * @Date: 2019/2/21 20:59
    10  * @Description: pattest
    11  * @Version: 1.0
    12  */
    13 public class PAT1027 {
    14     static final int size = 3;
    15     static char[] num = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C'};
    16 
    17     public static void main(String[] args) throws IOException {
    18         BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
    19         String[] split = reader.readLine().split(" ");
    20         System.out.print("#");
    21 
    22         for (int i = 0; i < size; i++) {
    23             StringBuilder stringBuilder = new StringBuilder();
    24             int n = Integer.parseInt(split[i]);
    25             do {
    26                 stringBuilder.append(num[n % 13]);
    27                 n %= 13;
    28             } while (n != 0);
    29             if (stringBuilder.length() <= 1)
    30                 System.out.print(num[0]);
    31             System.out.print(stringBuilder.reverse().toString());
    32         }
    33     }
    34 }
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  • 原文地址:https://www.cnblogs.com/PureJava/p/10498049.html
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