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  • 【POJ 1719】 Shooting Contest (二分图匹配)

    题目链接

    把每一列能射的两行和这一列连边,然后跑一边匈牙利就行了。

    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    using std::swap;
    #define Open(s) freopen(s".in","r",stdin);freopen(s".out","w",stdout);
    #define Close fclose(stdin);fclose(stdout);
    inline int read(){
    	int s = 0;
    	char ch = getchar();
    	while(ch < '0' || ch > '9') ch = getchar();
    	while(ch >= '0' && ch <= '9'){ s = s * 10 + ch - '0'; ch = getchar(); }
    	return s;
    }
    const int MAXN = 2010;
    int T, n, m, a[MAXN], b[MAXN], flag[MAXN], match[MAXN], c[MAXN], ans;
    struct Edge{
        int next, to;
    }e[MAXN << 1];
    int head[MAXN], num;
    inline void Add(int from, int to){
        e[++num].to = to;
        e[num].next = head[from];
        head[from] = num;
    }
    void print(){
    	for(int i = 1; i <= m; ++i){
            if(!match[i]) match[i] = a[i];
    		printf("%d ", match[i]);
        }
    	puts("");
    }
    int find(int x){
        for(int i = head[x]; i; i = e[i].next)
           if(!flag[e[i].to]){
             flag[e[i].to] = 1;
             if(!match[e[i].to] || find(match[e[i].to])){
               match[e[i].to] = x;
               return 1;
             }
           }
        return 0;
    }
    int Judge(){
        for(int i = 1; i <= m; ++i)
           c[match[i]] = T;
        for(int i = 1; i <= n; ++i)
           if(c[i] != T)
             return 1;
        return 0;
    }
    int main(){
    	Open("she");
    	T = read() + 1;
    	while(--T){
    		num = 0; for(int i = 1; i <= (m << 1); ++i) head[i] = 0;
    		n = read(); m = read();
    		for(int i = 1; i <= m; ++i){
    			a[i] = read(); b[i] = read(); 
    			Add(a[i], i); Add(b[i], i);
    			match[i] = 0;
    		}
    		for(int i = 1; i <= n; ++i){
               for(int i = 1; i <= m; ++i)
                  flag[i] = 0;
               find(i);
            }
            if(Judge()) printf("NO
    ");
            else print();
    	}
    	return 0;
    }
    
    
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  • 原文地址:https://www.cnblogs.com/Qihoo360/p/9713203.html
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