There is a game called "I Wanna Be the Guy", consisting of n levels. Little X and his friend Little Y are addicted to the game. Each of them wants to pass the whole game.
Little X can pass only p levels of the game. And Little Y can pass only q levels of the game. You are given the indices of levels Little X can pass and the indices of levels Little Y can pass. Will Little X and Little Y pass the whole game, if they cooperate each other?
Input
The first line contains a single integer n (1 ≤ n ≤ 100).
The next line contains an integer p (0 ≤ p ≤ n) at first, then follows p distinct integers a 1, a 2, ..., a p (1 ≤ a i ≤ n). These integers denote the indices of levels Little X can pass. The next line contains the levels Little Y can pass in the same format. It's assumed that levels are numbered from 1 to n.
Output
If they can pass all the levels, print "I become the guy.". If it's impossible, print "Oh, my keyboard!" (without the quotes).
Examples
input
4
3 1 2 3
2 2 4
output
I become the guy.
input
4
3 1 2 3
2 2 3
output
Oh, my keyboard!
Note
In the first sample, Little X can pass levels [1 2 3], and Little Y can pass level [2 4], so they can pass all the levels both.
In the second sample, no one can pass level 4.
分析
1 - n 如果全部出现了则输出 I become the guy.
不然输出 Oh, my keyboard!
#include<bits/stdc++.h>
using namespace std;
int n, _size, input; set<int>ans;
int main() {
cin >> n; for (int i = 2; i--;)for (cin >> _size; _size--;)cin >> input, ans.insert(input);
cout << (n == ans.size() ? "I become the guy.
" : "Oh, my keyboard!
");
}