Codewars题记 ：Find the missing letter

1、题目：

#Find the missing letter

Write a method that takes an array of consecutive (increasing) letters as input and that returns the missing letter in the array.

You will always get an valid array. And it will be always exactly one letter be missing. The length of the array will always be at least 2.
The array will always contain letters in only one case.

Example:

['a','b','c','d','f'] -> 'e'
['O','Q','R','S'] -> 'P'
(Use the English alphabet with 26 letters!)

Have fun coding it and please don't forget to vote and rank this kata! :-)

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2、我的解决方案

class Kata {
    public static char findMissingLetter(char[] array) {
        int nextASCLL = (int)array[0];
        
        int lostChar = 0;
        
        for (int i = 0; i < array.length; i++) {
            if ((int)array[i]!=nextASCLL) {
                lostChar = nextASCLL;
                break;
            }
            nextASCLL++;
        }
        
        return (char)lostChar;
    }
}

3、最佳解决方案

public class Kata
{
  public static char findMissingLetter(char[] array){
    char expectableLetter = array[0];
    for(char letter : array){
      if(letter != expectableLetter) break;
      expectableLetter++;
    }
    return expectableLetter;
  }
}

4、总结

　　这个题目主要是对char的ascll进行处理。

　　每次看最佳解决方案都能学习到最简单的写法。