C++int转化为string类型；string转化为int类型2

#include <iostream>
#include <string>
#include <vector>
#include <fstream>
#include <sstream>

using namespace std;

string int2str(int number)
{
    string strNumber;
    int result = abs(number);                                                               

    if (result == 0)
    {
        strNumber = "0";
    }
    else
    {
        while (result)
        {
            strNumber = (char)(result % 10 + '0' ) + strNumber;
            result /= 10;
        } 
    }

    if (number < 0)
        strNumber = "-" + strNumber;

    return strNumber;
}

int main(int argc, char *argv[])
{
    string strNumber = int2str(-797);
    cout << strNumber << endl;

    return 0;
}

这里是将int转化为string类型，思路是将int型数据除以10得到从而得到每一位。

#include <iostream>
#include <string>
#include <vector>
#include <fstream>
#include <sstream>

using namespace std;

int str2int(const string& strNumber)
{
    if (strNumber.length() == 0)
    {
        cout << "Input error!" << endl;
        return -1;
    }

    string tmpStr(strNumber);
    if (tmpStr[0] == '-')
        tmpStr.assign(tmpStr.begin() + 1, tmpStr.end());
    
    int number = 0;
    for (size_t i = 0; i < tmpStr.length(); i++)
    {
        number = number * 10 + (tmpStr[i] - '0');
    }

    if (strNumber[0] == '-')
        number *= -1;

    return number;
}

int main(int argc, char *argv[])
{
    int number = str2int(string("-70865"));
    cout << number << endl;

    return 0;
}

将string转化为int类型。