zoukankan      html  css  js  c++  java
  • Codeforces Round #166 (Div. 2) A. Beautiful Year【暴力枚举/逆向思维/大于当前数且每个位数不同】

    A. Beautiful Year
    time limit per test
    2 seconds
    memory limit per test
    256 megabytes
    input
    standard input
    output
    standard output

    It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

    Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

    Input

    The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

    Output

    Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

    Examples
    input
    1987
    output
    2013
    input
    2013
    output
    2014

    【题意】:给你一个数。求大于该数且每个位数不相同。四位数。
    【分析】:逆向思维,类似回文串,双重循环,一个指针遍历,另一个指针紧跟其后。两两一相等就return false了。
    【代码】:
    #include<cstdio>
    #include<iostream>
    #include<queue>
    #include<algorithm>
    using namespace std;
    bool check(int n)
    {
        int i=0,a[4],j;
        while(n)
        {
            a[i++]=n%10;
            n/=10;
        }
    
        for(int i=0;i<4;i++)
        {
            for(int j=i+1;j<4;j++)
            {
                if(a[i]==a[j])
                    return false;
            }
        }
        return true;
    }
    int main()
    {
        int n;
        while(cin>>n)
        {
            for(int i=n+1; ;i++)
            {
                if(check(i))
                {
                    cout<<i<<endl;
                    break;
                }
            }
        }
        return 0;
    }
    类似回文串的判断
  • 相关阅读:
    Python中的字典
    Python中的元组
    Python中常见的公共方法
    Python中的列表
    Python的循环语句
    Python的流程控制
    Kubernetes-kubectl命令出现错误【The connection to the server localhost:8080 was refused
    nyoj 77-开灯问题 (倍数遍历)
    nyoj 76-超级台阶 (递推)
    nyoj 75-日期计算 (闰年与平年的判断)
  • 原文地址:https://www.cnblogs.com/Roni-i/p/7923199.html
Copyright © 2011-2022 走看看