zoukankan      html  css  js  c++  java
  • Codeforces Beta Round #77 (Div. 2 Only) A. Football【字符串/判断是否存在连续7个0或7个1】

    A. Football
    time limit per test
    2 seconds
    memory limit per test
    256 megabytes
    input
    standard input
    output
    standard output

    Petya loves football very much. One day, as he was watching a football match, he was writing the players' current positions on a piece of paper. To simplify the situation he depicted it as a string consisting of zeroes and ones. A zero corresponds to players of one team; a one corresponds to players of another team. If there are at least 7 players of some team standing one after another, then the situation is considered dangerous. For example, the situation 00100110111111101 is dangerous and11110111011101 is not. You are given the current situation. Determine whether it is dangerous or not.

    Input

    The first input line contains a non-empty string consisting of characters "0" and "1", which represents players. The length of the string does not exceed 100 characters. There's at least one player from each team present on the field.

    Output

    Print "YES" if the situation is dangerous. Otherwise, print "NO".

    Examples
    input
    001001
    output
    NO
    input
    1000000001
    output
    YES

    【代码】:
    #include <bits/stdc++.h>
    
    using namespace std;
    int cnt=1;
    int main ()
    {
        string a;
        cin>>a;
        for(int i=0;i<a.size();i++)
        {
            if(a.find("0000000")!= a.npos||a.find("1111111")!= a.npos)
            {
                puts("YES");
                return 0;
            }
        }
        puts("NO");
        return 0;
    }
    

      

  • 相关阅读:
    那些陌生的C++关键字
    从实现装饰者模式中思考C++指针和引用的选择
    单例模式(Singleton)
    命令模式(Command)
    抽象工厂模式(Abstract Factory)
    《Effective C++》读书摘要
    桥接模式(Bridge)
    适配器模式(Adapter)
    设计模式学习心得
    黑客常用WinAPI函数整理
  • 原文地址:https://www.cnblogs.com/Roni-i/p/7989699.html
Copyright © 2011-2022 走看看