zoukankan      html  css  js  c++  java
  • HDU 2955 【01背包+小数概率】

    Robberies
    Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
    Total Submission(s): 29495 Accepted Submission(s): 10795

    Problem Description
    The aspiring Roy the Robber has seen a lot of American movies, and knows that the bad guys usually gets caught in the end, often because they become too greedy. He has decided to work in the lucrative business of bank robbery only for a short while, before retiring to a comfortable job at a university.

    For a few months now, Roy has been assessing the security of various banks and the amount of cash they hold. He wants to make a calculated risk, and grab as much money as possible.

    His mother, Ola, has decided upon a tolerable probability of getting caught. She feels that he is safe enough if the banks he robs together give a probability less than this.

    Input
    The first line of input gives T, the number of cases. For each scenario, the first line of input gives a floating point number P, the probability Roy needs to be below, and an integer N, the number of banks he has plans for. Then follow N lines, where line j gives an integer Mj and a floating point number Pj .
    Bank j contains Mj millions, and the probability of getting caught from robbing it is Pj .

    Output
    For each test case, output a line with the maximum number of millions he can expect to get while the probability of getting caught is less than the limit set.

    Notes and Constraints
    0 < T <= 100
    0.0 <= P <= 1.0
    0 < N <= 100
    0 < Mj <= 100
    0.0 <= Pj <= 1.0
    A bank goes bankrupt if it is robbed, and you may assume that all probabilities are independent as the police have very low funds.

    Sample Input
    3
    0.04 3
    1 0.02
    2 0.03
    3 0.05
    0.06 3
    2 0.03
    2 0.03
    3 0.05
    0.10 3
    1 0.03
    2 0.02
    3 0.05

    Sample Output
    2
    4
    6

    Source
    IDI Open 2009

  • 相关阅读:
    Flume配置
    HDU5312 Sequence
    CF(D. Fibonacci Sums)dp计数
    【算法拾遗】二分查找递归非递归实现
    ubuntu下怎么给普通用户赋予sudo权限
    在Oracle 11.2.0.1.0下dbms_stats.gather_table_stats收集直方图不准
    ZOJ3622 Magic Number(水题)
    小试ImageMagik——开发篇
    一起talk C栗子吧(第二十七回:C语言实例--插入排序)
    依据输入的内容打印出菱形
  • 原文地址:https://www.cnblogs.com/Roni-i/p/9057528.html
Copyright © 2011-2022 走看看