SDNU 1246.prime

这道题是很简单的题，我本来想用埃氏筛来解决，结果发现内存太大，爆掉了；就换了比较简单的办法去求；

这个故事告诉我们，这道题不能用埃氏筛。

Description

 This is a verrrrrrrrrry easy problem, when Lulichuan was a freshman, he can ease to judge whether a number is a prime， there some TestCase, you just need to judge if the number is a prime, if it’s a prime output  “N”, else output “Y”

Input

The first line is T(0 < T < 100000)

Then follow T line, every line is a number n(0 < n <100000000)

Output

As stated in the title

Sample Input

 5
 1
 2
 3
 4
 5

Sample Output

 Y
 N
 N
 Y
 N

#include <cstdio>
#include <iostream>
#include <cmath>
#include <algorithm>
#include <cstring>
using namespace std;

int main()
{
    int n;
    while(~scanf("%d", &n))
    {
        for(int i = 0; i < n; ++i)
        {
            int a;
            scanf("%d", &a);
            if(a == 1)
            {
                cout << 'Y' << '
';
                continue;
            }
            int j;
            for(j = 2; j <= sqrt(a); ++j)
            {
                if(a % j == 0)
                    break;
            }
            if(j > sqrt(a))
                cout << 'N' << '
';
            else
                cout << 'Y' << '
';
        }
    }
    return 0;
}