zoukankan      html  css  js  c++  java
  • CodeForces

    You are given a string tt consisting of nn lowercase Latin letters and an integer number kk .

    Let's define a substring of some string ss with indices from ll to rr as s[lr]s[l…r] .

    Your task is to construct such string ss of minimum possible length that there are exactly kk positions ii such that s[ii+n1]=ts[i…i+n−1]=t . In other words, your task is to construct such string ss of minimum possible length that there are exactly kk substrings of ss equal to tt .

    It is guaranteed that the answer is always unique.

    Input

    The first line of the input contains two integers nn and kk (1n,k501≤n,k≤50 ) — the length of the string tt and the number of substrings.

    The second line of the input contains the string tt consisting of exactly nn lowercase Latin letters.

    Output

    Print such string ss of minimum possible length that there are exactly kk substrings of ss equal to tt .

    It is guaranteed that the answer is always unique.

    Examples

    Input
    3 4
    aba
    Output
    ababababa
    Input
    3 2
    cat
    Output
    catcat
    #include <cstdio>
    #include <iostream>
    #include <cmath>
    #include <string>
    #include <cstring>
    #include <algorithm>
    #include <queue>
    using namespace std;
    int main()
    {
        int n, k, miao;
        string s, t;
        while(~scanf("%d%d", &n, &k) && (n+k))
        {
            cin >> s;
            miao = 0;
            for(int i = 1; i<n; i++)
            {
                t = s.substr(i);
                if(s.find(t) == 0)
                {
                    miao = i;
                    break;
                }
            }
            if(miao)
            {
                string root = s.substr(0, miao);
                for(int i = 0; i<k; i++)
                {
                    cout << root;
                }
                cout << t << '
    ';
            }
            else
            {
                for(int i = 0; i<k; i++)
                {
                    cout << s;
                }
            }
        }
        return 0;
    }
  • 相关阅读:
    c++数据类型
    c++注释
    c++基本语法
    c++环境配置
    c++简介
    9 HTTP和HTTPS
    12 RESTful架构(SOAP,RPC)
    剑指10二进制中1的个数
    第2章 新手必须掌握的Linux命令
    11个炫酷的Linux终端命令大全
  • 原文地址:https://www.cnblogs.com/RootVount/p/10467406.html
Copyright © 2011-2022 走看看