Given a list, rotate the list to the right by k places, where k is non-negative.
For example:
Given 1->2->3->4->5->NULL and k = 2,
return 4->5->1->2->3->NULL.
思考:先首尾连成环,head前进(len-k%len)步,拆环。
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *rotateRight(ListNode *head, int k) {
if(head==NULL||k==0) return head;
ListNode *p=head;
int len=1;
while(p->next)
{
len++;
p=p->next;
}
p->next=head;
k%=len;
int step=len-k;
while(step--)
{
p=p->next;
}
head=p->next;
p->next=NULL;
return head;
}
};