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  • [LeetCode]Subsets II

    Given a collection of integers that might contain duplicates, S, return all possible subsets.

    Note:

    • Elements in a subset must be in non-descending order.
    • The solution set must not contain duplicate subsets.

    For example,
    If S = [1,2,2], a solution is:

    [
      [2],
      [1],
      [1,2,2],
      [2,2],
      [1,2],
      []
    ]

    思考:直接set去重会不会太暴力。。

    class Solution {
    private:
        vector<vector<int> > res;
        vector<int> ans;
        set<vector<int> > m;
    public:
        void DFS(vector<int> S,int n,int start,int dep,int k)
        {
            if(dep==k)
            {
                set<vector<int> >::iterator iter=m.find(ans);
                if(iter==m.end())
                {
                    res.push_back(ans);
                    m.insert(ans);
                }
                return;
            }
            for(int i=start;i<n-k+1;i++)
            {
                ans.push_back(S[i+dep]);
                DFS(S,n,i,dep+1,k);
                ans.pop_back();
            }
        }
        vector<vector<int> > subsetsWithDup(vector<int> &S) {
            res.clear();
            ans.clear();
            int n=S.size();
            sort(S.begin(),S.end());
            for(int k=0;k<=n;k++)
            {
                DFS(S,n,0,0,k);
            }
            return res;
        }
    };
    

      

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  • 原文地址:https://www.cnblogs.com/Rosanna/p/3521290.html
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