Given a collection of integers that might contain duplicates, S, return all possible subsets.
Note:
- Elements in a subset must be in non-descending order.
- The solution set must not contain duplicate subsets.
For example,
If S = [1,2,2], a solution is:
[ [2], [1], [1,2,2], [2,2], [1,2], [] ]
思考:直接set去重会不会太暴力。。
class Solution {
private:
vector<vector<int> > res;
vector<int> ans;
set<vector<int> > m;
public:
void DFS(vector<int> S,int n,int start,int dep,int k)
{
if(dep==k)
{
set<vector<int> >::iterator iter=m.find(ans);
if(iter==m.end())
{
res.push_back(ans);
m.insert(ans);
}
return;
}
for(int i=start;i<n-k+1;i++)
{
ans.push_back(S[i+dep]);
DFS(S,n,i,dep+1,k);
ans.pop_back();
}
}
vector<vector<int> > subsetsWithDup(vector<int> &S) {
res.clear();
ans.clear();
int n=S.size();
sort(S.begin(),S.end());
for(int k=0;k<=n;k++)
{
DFS(S,n,0,0,k);
}
return res;
}
};