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  • [LeetCode]Interleaving String

    Given s1s2s3, find whether s3 is formed by the interleaving of s1 and s2.

    For example,
    Given:
    s1 = "aabcc",
    s2 = "dbbca",

    When s3 = "aadbbcbcac", return true.
    When s3 = "aadbbbaccc", return false.

    class Solution {
    private:
        bool f[1000][1000];
    public:
        bool isInterleave(string s1, string s2, string s3) {
            // Start typing your C/C++ solution below
            // DO NOT write int main() function 
            if (s1.size() + s2.size() != s3.size())
                return false;
                
            f[0][0] = true;
            for(int i = 1; i <= s1.size(); i++)
                f[i][0] = f[i-1][0] && (s3[i-1] == s1[i-1]);
                
            for(int j = 1; j <= s2.size(); j++)
                f[0][j] = f[0][j-1] && (s3[j-1] == s2[j-1]);
                
            for(int i = 1; i <= s1.size(); i++)
                for(int j = 1; j <= s2.size(); j++)
                    f[i][j] = (f[i][j-1] && s2[j-1] == s3[i+j-1]) || (f[i-1][j] && s1[i-1] == s3[i+j-1]);
                    
            return f[s1.size()][s2.size()];
        }
    };
    

      

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  • 原文地址:https://www.cnblogs.com/Rosanna/p/3598396.html
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