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  • 暴力 Codeforces Round #305 (Div. 2) B. Mike and Fun

    题目传送门

     1 /*
     2     暴力:每次更新该行的num[],然后暴力找出最优解就可以了:)
     3 */
     4 #include <cstdio>
     5 #include <cstring>
     6 #include <iostream>
     7 #include <algorithm>
     8 #include <string>
     9 using namespace std;
    10 
    11 const int MAXN = 5e2 + 10;
    12 const int INF = 0x3f3f3f3f;
    13 int a[MAXN][MAXN];
    14 int num[MAXN];
    15 int n, m;
    16 
    17 int work(int x)
    18 {
    19     int res = 0;
    20     for (int j=1;j<=m; ++j)
    21     {
    22         if (a[x][j] == 1)
    23         {
    24             int cnt = 0;
    25             while (a[x][j] == 1)    ++j, ++cnt;
    26             res = max (res, cnt);
    27         }
    28     }
    29 
    30     return res;
    31 }
    32 
    33 int main(void)        //Codeforces Round #305 (Div. 2) B. Mike and Fun
    34 {
    35     int q;
    36     while (scanf ("%d%d%d", &n, &m, &q) == 3)
    37     {
    38         for (int i=1; i<=n; ++i)
    39         {
    40             for (int j=1; j<=m; ++j)    scanf ("%d", &a[i][j]);
    41         }
    42         int ans = 0;
    43         for (int i=1; i<=n; ++i)    num[i] = work (i);
    44         while (q--)
    45         {
    46             int x, y;
    47             scanf ("%d%d", &x, &y);
    48             a[x][y] = 1 - a[x][y];    num[x] = work (x);
    49             int ans = 0;
    50             for (int i=1; i<=n; ++i)    ans = max (ans, num[i]);
    51             printf ("%d
    ", ans);
    52         }
    53     }
    54 
    55     return 0;
    56 }
    57 
    58 /*
    59 5 4 5
    60 0 1 1 0
    61 1 0 0 1
    62 0 1 1 0
    63 1 0 0 1
    64 0 0 0 0
    65 1 1
    66 1 4
    67 1 1
    68 4 2
    69 4 3
    70 */
    编译人生,运行世界!
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  • 原文地址:https://www.cnblogs.com/Running-Time/p/4534179.html
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