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  • BestCoder Round #54 (div.2) 1003 Geometric Progression

    题目传送门

    题意:判断是否是等比数列

    分析:高精度 + 条件:a[i] * a[i+2] == a[i+1] * a[i+1]。特殊情况:0 0 0 0 0是Yes的,1 2 0 9 2是No的

     

    代码:

    /************************************************
    * Author        :Running_Time
    * Created Time  :2015-9-5 20:06:46
    * File Name     :C.cpp
     ************************************************/
    
    #include <cstdio>
    #include <algorithm>
    #include <iostream>
    #include <sstream>
    #include <cstring>
    #include <cmath>
    #include <string>
    #include <vector>
    #include <queue>
    #include <deque>
    #include <stack>
    #include <list>
    #include <map>
    #include <set>
    #include <bitset>
    #include <cstdlib>
    #include <ctime>
    using namespace std;
    
    #define lson l, mid, rt << 1
    #define rson mid + 1, r, rt << 1 | 1
    typedef long long ll;
    const int N = 1e2 + 10;
    const int INF = 0x3f3f3f3f;
    const int MOD = 1e9 + 7;
    const int numlen = 2005; // 需要的位数
    const int numbit = 4;   // 数组一位表示的整数
    const int addbit = 10000;//进位数
    const int maxn = numlen/numbit + 10;   // 数组要开的位数
    
    int max(int a, int b) { return a>b?a:b; }
    struct bign {
        int len, s[numlen];
        bign() {
            memset(s, 0, sizeof(s));
            len = 1;
        }
        bign(int num) { *this = num; }
        bign(const char *num) { *this = num; }
        bign operator = (const int num) {
            char s[numlen];
            sprintf(s, "%d", num);
            *this = s;
            return *this;
        }
        bign operator = (const char *num) {
            int clen = strlen(num);
            while(clen > 1 && num[0] == '0') num++, clen--;
            len = 0;
            for(int i = clen-1;i >= 0;i -= numbit) {
                int top = min(numbit, i+1), mul = 1;
                s[len] = 0;
                for(int j = 0;j < top; j++) {
                    s[len] += (num[i-j]-'0')*mul;
                    mul *= 10;
                }
                len++;
            }
            deal();
            return *this;
        }
    
        void deal() {
            while(len > 1 && !s[len-1]) len--;
        }
    
        bign operator + (const bign &a) const {
            bign ret;
            ret.len = 0;
            int top = max(len, a.len) , add = 0;
            for(int i = 0;add || i < top; i++) {
                int now = add;
                if(i < len) now += s[i];
                if(i < a.len)   now += a.s[i];
                ret.s[ret.len++] = now%addbit;
                add = now/addbit;
            }
            return ret;
        }
        bign operator - (const bign &a) const {
            bign ret;
            ret.len = 0;
            int cal = 0;
            for(int i = 0;i < len; i++) {
                int now = s[i] - cal;
                if(i < a.len)   now -= a.s[i];
                if(now >= 0)    cal = 0;
                else {
                    cal = 1; now += addbit;
                }
                ret.s[ret.len++] = now;
            }
            ret.deal();
            return ret;
        }
        bign operator * (const bign &a) const {
            bign ret;
            ret.len = len + a.len;
            for(int i = 0;i < len; i++) {
                int pre = 0;
                for(int j = 0;j < a.len; j++) {
                    int now = s[i]*a.s[j] + pre;
                    pre = 0;
                    ret.s[i+j] += now;
                    if(ret.s[i+j] >= addbit) {
                        pre = ret.s[i+j]/addbit;
                        ret.s[i+j] -= pre*addbit;
                    }
                }
                if(pre) ret.s[i+a.len] = pre;
            }
            ret.deal();
            return ret;
        }
    
        //乘以小数,直接乘快点  ***********注意计算过程可能会爆int
        bign operator * (const int num) {
            bign ret;
            ret.len = 0;
            int bb = 0;
            for(int i = 0;i < len; i++) {
                int now = bb + s[i]*num;
                ret.s[ret.len++] = now%addbit;
                bb = now/addbit;
            }
            while(bb) {
                ret.s[ret.len++] = bb % addbit;
                bb /= addbit;
            }
            ret.deal();
            return ret;
        }
        // 除以一个小整数     ***********注意计算过程可能会爆int
        bign operator / (const int a) const {
            bign ret;
            ret.len = len;
            int pre = 0;
            for(int i = len-1;i >= 0; i--) {
                ret.s[i] = (s[i] + pre*addbit)/a;
                pre = s[i] + pre*addbit - a*ret.s[i];
            }
            ret.deal();
            return ret;
        }
    
    
        bign operator % (const int a) const {
            bign b = *this / a;
            return *this - b*a;
        }
    
        bign operator += (const bign &a) { *this = *this + a; return *this; }
        bign operator -= (const bign &a) { *this = *this - a; return *this; }
        bign operator *= (const bign &a) { *this = *this * a; return *this; }
        bign operator /= (const int a) { *this = *this / a; return *this; }
        bign operator %= (const int a) { *this = *this % a; return *this; }
    
        bool operator < (const bign &a) const {
            if(len != a.len)    return len < a.len;
            for(int i = len-1;i >= 0; i--) if(s[i] != a.s[i])
                return s[i] < a.s[i];
            return false;
        }
        bool operator > (const bign &a) const  { return a < *this; }
        bool operator <= (const bign &a) const { return !(*this > a); }
        bool operator >= (const bign &a) const { return !(*this < a); }
        bool operator == (const bign &a) const { return !(*this > a || *this < a); }
        bool operator != (const bign &a) const { return *this > a || *this < a; }
    
        void print() {
            printf("%d", s[len-1]);
            for(int i = len-2;i >= 0; i--) {
                printf("%04d", s[i]);
            }
            puts("");
        }
    
        string str() const {
            string ret = "";
            for(int i = 0;i < len; i++) ret = char(s[i] + '0') + ret;
            return ret;
        }
    };
    istream& operator >> (istream &in, bign &x) {
        string s;
        in >> s;
        x = s.c_str();
        return in;
    }
    ostream& operator << (ostream &out, const bign &x) {
        printf("%d", x.s[x.len-1]);
        for(int i = x.len-2;i >= 0; i--)    printf("%04d", x.s[i]);
        return out;
    }
    bign a[N];
    
    int main(void)    {
    	int T;	scanf ("%d", &T);
    	while (T--)	{
    		int n;	scanf ("%d", &n);
    		for (int i=1; i<=n; ++i)	cin >> a[i];
    		bool flag = true;	int zero = 0;
    		for (int i=1; i<=n; ++i)	{
    			if (a[i] == 0)	{
    				zero++;
    			}
    		}
    		if (n == 1 || zero == n)	{
    			puts ("Yes");	continue;
    		}
    		if (zero > 0)	{
    			puts ("No");	continue;
    		}
    		else	{
                for (int i=1; i<=n-2; ++i)	{
    				if (a[i] * a[i+2] != a[i+1] * a[i+1])	{
    					flag = false;	break;
    				}
                }
    		}
    
    		puts (flag ? "Yes" : "No");
    	}
    
        return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/Running-Time/p/4785349.html
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