DFS(剪枝) POJ 1724 ROADS

题目传送门

题意：问从1到n的最短路径，同时满足花费总值小于等于k

分析：深搜+剪枝，如果之前走过该点或者此时的路劲长度大于最小值就不进行搜索。

/************************************************
* Author        :Running_Time
* Created Time  :2015/11/11 星期三 10:14:14
* File Name     :POJ_1724.cpp
 ************************************************/

//#include <bits/stdc++.h>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <queue>
#include <cmath>
using namespace std;

#define lson l, mid, rt << 1
#define rson mid + 1, r, rt << 1 | 1
typedef long long ll;
const int N = 1e2 + 10;
const int E = 1e4 + 10;
const int INF = 0x3f3f3f3f;
const int MOD = 1e9 + 7;
const double EPS = 1e-10;
const double PI = acos (-1.0);
int k, n, m;
struct Edge {
    int v, w, len, nex;
    Edge () {}
    Edge (int v, int w, int len, int nex) : v (v), w (w), len (len), nex (nex) {}
}edge[E];
int head[N], d[N];
bool vis[N];
int e;

void init(void) {
    memset (head, -1, sizeof (head));
    e = 0;
}

void add_edge(int u, int v, int w, int len) {
    edge[e] = Edge (v, w, len, head[u]);
    head[u] = e++;
}

int ans;
void DFS(int u, int L, int cost)    {
    if (u == n) {
        if (L < ans)    ans = L;
        return ;
    }
    for (int i=head[u]; ~i; i=edge[i].nex)  {
        Edge &r = edge[i];
        if (cost - r.w < 0 || L + r.len > ans)  continue;
        if (vis[r.v])   continue;
        vis[r.v] = true;
        DFS (r.v, L + r.len, cost - r.w);
        vis[r.v] = false;
    }
}

int main(void)    {
    while (scanf ("%d%d%d", &k, &n, &m) == 3)   {
        init ();
        for (int u, v, w, len, i=1; i<=m; ++i)    {
            scanf ("%d%d%d%d", &u, &v, &len, &w);
            add_edge(u, v, w, len);
        }
        ans = INF;
        memset (vis, false, sizeof (vis));
        vis[1] = true;
        DFS (1, 0, k);
        if (ans == INF) ans = -1;
        printf ("%d
", ans);
    }

   //cout << "Time elapsed: " << 1.0 * clock() / CLOCKS_PER_SEC << " s.
";

    return 0;
}