Given a non-empty integer array of size n, find the minimum number of moves required to make all array elements equal, where a move is incrementing n - 1 elements by 1.
Example:
Input: [1,2,3] Output: 3 Explanation: Only three moves are needed (remember each move increments two elements): [1,2,3] => [2,3,3] => [3,4,3] => [4,4,4]
思路:
题目希望用最少的步骤是的所有的数字相同,每次n-1个元素加1,观察例子可以看出每次是的不是最大的n-1个数字加1,那么转换过来就是每次使最大的那个数字减1,所以为了是的数组一致,所有的数字都必然会减到最小的那个数字。
1 class Solution { 2 public: 3 int minMoves(vector<int>& nums) { 4 if(nums.size()==0) 5 return 0; 6 int min_num=nums[0]; 7 for(int n:nums) 8 min_num=min(min_num,n); 9 int res=0; 10 for(int n:nums) 11 res+=n-min_num; 12 return res; 13 } 14 };