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  • 第五次作业

    词法分析程序(Lexical Analyzer)要求:

    - 从左至右扫描构成源程序的字符流

    -  识别出有词法意义的单词(Lexemes

    -  返回单词记录(单词类别,单词本身)

    -  滤掉空格

    -  跳过注释

    -  发现词法错误

    程序结构:

    输入:字符流(什么输入方式,什么数据结构保存)

    处理:

    –遍历(什么遍历方式)

    –词法规则

    输出:单词流(什么输出形式)

    –二元组

    单词类别:

    1.标识符(10)

    2.无符号数(11)

    3.保留字(一词一码)

    4.运算符(一词一码)

    5.界符(一词一码)

    单词符号

    种别码

    单词符号

    种别码

    begin

    1

    :

    17

    if

    2

    :=

    18

    then

    3

    <

    20

    while

    4

    <=

    21

    do

    5

    <>

    22

    end

    6

    >

    23

    l(l|d)*

    10

    >=

    24

    dd*

    11

    =

    25

    +

    13

    ;

    26

    -

    14

    (

    27

    *

    15

    )

    28

    /

    16

    #

    0

    代码:

    #include<stdio.h>
    #include <iostream>
    #include<string.h>
    using namespace std;
    char *reserved[6] = {"begin","if","then","while","do","end"};
    char input[80],output[8];
    char ch;
    int syn,p,i;
    int m = 0,n,row,sum = 0,count=0;
    void scanner(){
    for( i = 0 ; i < 8 ; i++ ){
    output[i] = NULL;
    }
    ch = input[p++];

    while( ch == ' ' ){
    ch = input[p] ;
    p ++ ;
    }
    if( ( ch >= 'a' && ch <= 'z' ) || ( ch >= 'A' && ch <= 'Z' ) ){
    m = 0 ;
    while( ( ch >= 'a' && ch <= 'z' ) || ( ch >= 'A' && ch <= 'Z' ) || ( ch >= '0' && ch <= '9' ) ){
    output[m++] = ch ;
    ch = input[p++];
    }
    output[m++] = '';
    p -- ;
    syn = 10 ;
    for( n = 0 ; n < 6 ; n ++ ){
    if( strcmp(output,reserved[n]) == 0 ){
    syn = n + 1;
    break;
    }
    }

    }else if( ( ch >= '0' && ch <= '9' ) ){
    sum = 0 ;
    while( ch >= '0' && ch <= '9' ){
    sum=sum*10+ch-'0' ;
    ch = input[p++] ;
    }
    p -- ;
    syn = 11;
    }
    else if(ch == '/'){
    ch = input[p++] ;
    if(ch == '/'){
    while(ch != ' '){
    ch = input[p++] ;
    }
    scanner();
    }
    else if(ch == '*'){
    ch = input[p++];
    int flag=0;
    while((ch == '*' && input[p] != '/')||(ch != '*' && input[p] == '/') || (ch != '*' && input[p] != '/')){
    ch = input[p++] ;
    if(p==count-2 && (ch != '*' && input[p] != '/')){
    flag =1;
    syn = 100;
    break;
    }
    }
    p++;
    if(flag==0){
    scanner();
    }
    }else{
    p = p - 2 ;
    ch = input[p++] ;
    output[0] = ch ;
    syn = 16 ;
    }
    }else switch(ch){
    case '+':
    output[0] = ch ;
    syn = 13;
    break;
    case '-':
    output[0] = ch ;
    syn = 14;
    break;
    case '*':
    output[0] = ch ;
    syn = 15 ;
    break;
    case '/':
    output[0] = ch ;
    syn = 16 ;
    break;
    case ':':
    i = 0;
    output[i++] = ch ;
    ch = input[p++];
    if( ch == '=' ){
    output[i++] = ch;
    syn = 18 ;
    }else{
    syn = 17;
    p-- ;
    }
    break;
    case '<':
    i = 0 ;
    output[i++] = ch ;
    ch = input[p++] ;
    if( ch == '=' ){
    output[i++] = ch ;
    syn = 21 ;
    }else if( ch == '>' ){
    output[i++] = ch ;
    syn = 22 ;
    }else{
    syn = 20 ;
    p-- ;
    }
    break;
    case '>':
    i = 0;
    output[i++] = ch ;
    ch = input[p++] ;
    if( ch == '=' ){
    output[i++] = ch;
    syn=24;
    }else{
    syn=23;
    p--;
    }
    break;
    case '=':
    output[0] = ch ;
    syn = 25 ;
    break;
    case ';':
    output[0] = ch ;
    syn = 26 ;
    break;
    case '(':
    output[0] = ch ;
    syn = 27 ;
    break;
    case ')':
    output[0] = ch ;
    syn = 28 ;
    break;
    case '#':
    output[0] = ch ;
    syn = 0;
    break;
    case ' ':
    syn = 99 ;
    break;
    default:
    syn = -1 ;
    break;
    }

    }
    int main() {
    p = 0;
    printf("请输入程序:");
    do{
    ch = getchar();
    input[p++] = ch;
    }while(ch != '#');
    count = p;
    p = 0;
    printf(" 单词符号 种别码 ");
    do{
    scanner();
    switch(syn){
    case -1:
    printf("在第%d行有错误!",row+1);
    break;
    case 11:
    printf(" %d %d ",sum,syn);
    break;
    case 99:
    row+=1;
    break;
    case 100:
    printf("注释到尾结束! ");
    break;
    default:
    printf(" %s %d ",output,syn);
    break;
    }
    }while(syn != 0);
    return 0;
    }

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  • 原文地址:https://www.cnblogs.com/SeBr7/p/11656316.html
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