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  • .net 面试题(3)

    96、题目:

    活期存款中,“储户”通过“存取款单”和“储蓄所”发生联系。假定储户包括:账号,姓名,电话,地址,存款额;“储蓄所”包括:储蓄所编号,名称,电话,地址(假定一个储户可以在不同得储蓄所存取款)
    1、写出设计以上表格的语句。  

    Create table 储户
    
    ( 账号 int primary key,姓名char(10),电话 int,地址 nvarchar(50),存款金额 money  )
    
      Create table 储蓄所
    
     (  编号 int primary key,名称 char(10),电话 int,地址 nvarchar(50)   )
    
      Create table  存取款单
    
     ( 账号 Int not null,编号 Int not null,时间 datetime not null, 存取标志 int not null,存取金额 money )

    2、创建一个触发器TR1完成下面内容:
    当向“存取款单”表中插入数据时,如果存取标志=1则应该更改储户表让存款额加上存取金额,如果存取标志=0则应该更改储户表让存款额减去存取金额,如果余额不足显示余额不足错误。

      Create trigger InsertInfo on 存取款单 for insert 
           As 
          Declare @BZ int,@money money,@zh int
         Select @BZ=存取标志,@money=存取金额,@zh=账号
           From inserted   //从inserted 表中得到插入的记录信息
         If @BZ=0    //取钱
           Begin
             Declare @sy money
             Select @sy=存款金额 from 储户  //拿到用户的存款金额
             If (@sy<@money)  //如果存款金额小于所取的金额,说明金额不够
              begin
                    raiserror ('余额不足')
                    rollback
              End
           Else
            begin
                 Update 储户 set 存款金额-=@money where 账号=@zh   //更新储户表
            End 
            end
          If @BZ=1
          Begin
              Update 储户 set 存款金额+=@money where 账号=@zh
          end

    97、本题用到下面三个关系表:

    CARD     借书卡:   (CNO 卡号,NAME  姓名,CLASS 班级)

    BOOKS    图书:     (BNO 书号,BNAME 书名,AUTHOR 作者,PRICE 单价,QUANTITY 库存册数 )

    BORROW   借书记录: (CNO 借书卡号,BNO 书号,RDATE 还书日期

    备注:限定每人每种书只能借一本;库存册数随借书、还书而改变。

    要求实现如下处理:

    1. 写出自定义函数,要求输入借书卡号能得到该卡号所借书金额的总和

     Create function fun_GetPrice
           (   @cno int  )
          Returns money   //指定函数的类型
          As
           Begin
              Declare @sum money
             Select @sum=sum(price) from book where bno in (select BNO from borrow where CNO=@cno )
          Return @sum  //函数的最后一条必须是return语句
           end

    2. 找出借书超过5本的读者,输出借书卡号及所借图书册数。

      Select CNO,Count(bno) as 借书数量 from borrow group by CNO having Count(bno)>3

    3. 查询借阅了"水浒"一书的读者,输出姓名及班级。  

     Select Name,Class from Card where CNO in (select CNO from borrow where BNO in(select BNO from books where  bname=’水浒’ ) ) 

    4. 查询过期未还图书,输出借阅者(卡号)、书号及还书日期。  

      Select CNO,BNO,RDate from borrow where RDate<getdate() 

    5. 查询书名包括"网络"关键词的图书,输出书号、书名、作者。    

     Select BNO,BName,AUTHOR from books where BName like ‘%网络%’ 

    6. 查询现有图书中价格最高的图书,输出书名及作者。 

        Select BName,AUTHOR from books where price in(select max(prcie) from  books)

    7. 查询当前借了"计算方法"但没有借"计算方法习题集"的读者,输出其借书卡号,并按卡号降序排序输出。

    Select CNO from borrow where BNO in (select BNO from books Where bname=’计算方法’) and cno not in (select cno from borrow where 
    bno in (select bno from books where bname=’计算方法习题集’))order by cno

     

    98.创建以下表结构,并添加一些测试数据:

    Student(S#,Sname,Sage,Ssex) 学生表 

    Course(C#,Cname,T#) 课程表 

    SC(S#,C#,score) 成绩表 

    Teacher(T#,Tname) 教师表 

     

    1. 查询001课程比002课程成绩高的所有学生的学号;  

    /*1 */ select c1.s# from Sc as c1,Sc as c2 where c1.s#=c2.s# and c1.c#='001'
       and c2.c#='002'  and c1.score>c2.score   
    /*2 */ select a.s# from (select s#,score from Sc where c#='001')a,(select s#,score 
       from Sc where c#='002')b where a.score>b.score and a.s#=b.s# 

    2. 查询平均成绩大于60分的同学的学号和平均成绩; 

       select S#,AVG(score) from Sc group by s# having AVG(score)>60 

    3. 查询所有同学的学号、姓名、选课数、总成绩;  

       select stu.s#,stu.sname,COUNT(C.c#),SUM(c.score) from Student as stu,Sc as c
        where stu.s#=c.s# group by stu.s#,stu.sname   - - 和聚合函数出现在一起的列,必须都在group by 语句中出现

    4. 查询姓的老师的个数;  

    1、 select COUNT(tname),tname from Teacher where tname like '杨%' group by tname  --如果没有不会显示信息
    2、 select COUNT(distinct(tname)) from Teacher where tname like '杨%' --distinct 排除重复的列

    5. 查询没学过叶平老师课的同学的学号、姓名;  

    1、 select stu.s#,stu.sname from Student as stu where stu.s# not in
     (select s.s# from sc as s where s.c# in  (select c.c# from Teacher as t,Course as c where t.t#=c.t# and tname='叶平'))
    
    2、
    select stu.s#,stu.sname from Student as stu where stu.s# not in (select c.s# from Sc as c,Course as cc,Teacher
    as t where c.c#=cc.c# and cc.t#=t.t# and t.tname='叶平') --三表查询,这个写起来简单

      6.查询学过“001”并且也学过编号“002”课程的同学的学号、姓名; 

     select stu.s#,stu.sname from Student as stu where stu.s# in (select c1.s# from Sc as c1,Sc as c2 where c1.s#=c2.s# 
    and c1.c#='001' and c2.c#='002') --先找出学了001和002的同学的学号,类似第一题

      7.查询学过“叶平”老师所教的所有课的同学的学号、姓名;

    select stu.s#,stu.sname from Student as stu where stu.s# in (select c.s# from sc as c,Course as cc,Teacher as t where 
       c.c#=cc.c# and cc.t#=t.t# and t.tname='叶平')  --跟第5题相反   

      8.查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、姓名;

     select stu.s#,stu.sname from Student as stu where stu.s# in (select c2.s# from Sc as c1,Sc as c2 where c1.s#=c2.s# 
    and c2.c#='002' and c1.c#='001' and c2.score<c1.score)

      9.查询所有课程成绩小于60分的同学的学号、姓名;

     select stu.s#,stu.sname from Student as stu where stu.s# not in (select hh.s# from Sc as c,Student as hh where
    hh.s#=c.s# and c.score>60)

    10.查询没有学全所有课的同学的学号、姓名;

    select s.s#,s.sname from Student as s,Sc as c where s.s#=c.s#  group by s.s#,s.sname having COUNT(c#) <
    (select COUNT(C#) from Course) 

    11.查询至少有一门课与学号为“1001”的同学所学相同的同学的学号和姓名; 

    select distinct stu.s#,stu.sname  from Student as stu,Sc as c where stu.s#=c.s#  and  c.c# in (select c# from Sc where s#='1001')

    12.查询至少学过学号为“001”同学所有一门课的其他同学学号和姓名; 

    select distinct stu.s#,stu.sname from Student as stu,Sc where stu.s#=sc.s# and c# in   (select c# from Sc where Sc.s#='001') 

    13.把“SC”表中“叶平”老师教的课的成绩都更改为此课程的平均成绩; 

     update Sc set  sc.score=( select AVG(c.score) from Sc as c,Course,Teacher where  c.c#=Course.c# and  
    Course.t#=Teacher.t# and Teacher.tname='叶平' and c.c#=sc.c#)

    14.查询和“1002”号的同学学习的课程完全相同的其他同学学号和姓名; 

    select Student.s#,Student.sname from Student,Sc where Student.s#=sc.s# and    Sc.c# in(select sc.c# from Sc where sc.s#='002') and sc.s#!='002'
        group by Student.s#,Student.sname having COUNT(c#)=(select COUNT(c#) from Sc where sc.s#='002')

    15.删除学习“叶平”老师课的SC表记录; 

     delete Sc where sc.c#=(select Course.c# from Course,Teacher where Course.t#=Teacher.t# and  Teacher.tname='叶平')

     16.SC表中插入一些记录,这些记录要求符合以下条件:没有上过编号“003”课程的同学学号、2号课的平均成绩;

    insert Sc select s#,'002',(select AVG(score) from Sc where c#='002' ) from Student   where s# not in (select s# from sc where c#='003')

    17.按平均成绩从高到低显示所有学生的“数据库”、“企业管理”、“英语”三门的课程成绩,按如下形式显示: 学生ID,,数据库,企业管理,英语,有效课程数,有效平均分 

    select s# as 学生ID,(select score from Sc where sc.s#=t.s# and c#='004') as 数据库,
     (select score from Sc where sc.s#=t.s# and c#='001') as 企业管理,
     (select score from Sc where sc.s#=t.s# and c#='006') as 英语
    from Sc as t group by s# order by AVG(score)

    18.查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分 

     select c#,max(score),min(score) from sc group by c#

    19.按各科平均成绩从低到高和及格率的百分数从高到低顺序 

    select sc.c#,cname,isnull(avg(score),0) as 平均成绩,100*SUM(case when isnull(score,0)>60 then 1 else 0 end)/count(*) as 及格率 from sc,
    Course where sc.c#=Course.c# group by sc.c#,cname order by AVG(score), 
    100*SUM(case when isnull(score,0)>60 then 1 else 0 end)/count(*) desc

    20.统计列印各科成绩,各分数段人数:课程ID,课程名称,[100-85],[85-70],[70-60],[ <60](红色为列名)

    select sc.c#,cname,
    sum(case when score between  85 and 100 then 1 else 0 end) as [100-85],
    sum(case when score between  85 and 70 then 1 else 0 end) as [85-70],
    sum(case when score between  70 and 60 then 1 else 0 end) as [70-60],
    sum(case when score <60 then 1 else 0 end) as [<60]
     from  sc,Course where sc.c#=Course.c# group by sc.c#,cname

    21.查询每门课程被选修的学生数 

    select C#,COUNT(S#) from sc group by c#

    22.查询出只选修了一门课程的全部学生的学号和姓名 

    select Student.s#,Student.sname,COUNT(C#) from sc,Student  where sc.s#=Student.s#  group by Student.s#,Student.sname having  COUNT(C#)=1

    23.查询男生、女生人数

    select count(ssex) from Student where ssex=''
    select count(ssex) from Student where ssex=''

    24.查询姓“张”的学生名单 

    select sname from Student where sname like '张%'

    25.查询同名同性学生名单,并统计同名人数

    select Student.sname,COUNT(*) from Student group by Student.sname having COUNT(*)>1

    26.1981年出生的学生名单(注:Student表中Sage列的类型是datetime)

     select sname,CONVERT(int,DATEPART(year,sage)) as 年纪 from Student  where CONVERT(int,DATEPART(year,sage))='1981'
    CONVERT() 函数可以用不同的格式显示日期/时间数据。

    27.查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列 

    select c#,AVG(score) from sc group by c# order by AVG(score),c# DESC

    28.查询平均成绩大于85的所有学生的学号、姓名和平均成绩 

    select sc.s#,Student.sname,avg(score) from Student,sc where Student.s#=sc.s# group by sc.s#,Student.sname having AVG(score)>85

    29.查询课程名称为“数据库”,且分数低于60的学生姓名和分数

    select Student.s#,sc.score from Student,sc,Course where Student.s#=sc.s# and sc.c#=Course.c# and cname='数据库' and score<60

    30.查询所有学生的选课情况; 

    select Student.s#,sc.c#,sname,cname from Student,sc,Course where Student.s#=sc.s# and sc.c#=Course.c#

    31.查询任何一门课程成绩在70分以上的姓名、课程名称和分数; 

    select sname,cname,score from Student,Course,sc where Student.s#=sc.s# and sc.c#=Course.c# and score>70

    32.查询不及格的课程,并按课程号从大到小排列 ;

    select sc.c#,cname from sc,Course where sc.c#=Course.c# and score<60 group by sc.c# order by sc.c# desc

    33.查询课程编号为003且课程成绩在80分以上的学生的学号和姓名; 

    select Student.s#,sname from Student,sc where Student.s#=sc.s# and sc.c#='003' and score>80

    34.求选了课程的学生人数 ;

      select count(s#) from sc

    35.查询选修“叶平”老师所授课程的学生中,成绩最高的学生姓名及其成绩 ;

     select Student.sname,sc.score  from student,sc,Course,Teacher where tname='叶平'  and Student.s#=sc.s# and sc.c#=Course.c# and 
    Course.t#=Teacher.t# and sc.score=(select max(score) from sc where sc.c#=Course.c#)
    DATEPART
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  • 原文地址:https://www.cnblogs.com/Sea1ee/p/5994912.html
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