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  • [LeetCode]Search a 2D Matrix II

    Search a 2D Matrix II

    Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:

    • Integers in each row are sorted in ascending from left to right.
    • Integers in each column are sorted in ascending from top to bottom.

    For example,

    Consider the following matrix:

    [
      [1,   4,  7, 11, 15],
      [2,   5,  8, 12, 19],
      [3,   6,  9, 16, 22],
      [10, 13, 14, 17, 24],
      [18, 21, 23, 26, 30]
    ]
    

    Given target = 5, return true.

    Given target = 20, return false.

    采用分治发,用上题的方法二代码即可,都不需要改的。

     1 class Solution {
     2 public:
     3     bool searchMatrix(vector<vector<int>>& matrix, int target) {
     4         if(matrix.size()==0 || matrix[0].size()==0) return false;
     5         int m=matrix.size(),n=matrix[0].size();
     6         int row=0,col=n-1;
     7         while(row<m && col>=0)
     8         {
     9             if(matrix[row][col]==target) return true;
    10             else if(matrix[row][col]<target) row++;
    11             else col--;
    12         }
    13         return false;
    14     }
    15 };
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  • 原文地址:https://www.cnblogs.com/Sean-le/p/4805572.html
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