zoukankan      html  css  js  c++  java
  • 交互题(apio2016Gap)

    题目链接

     
    //Serene
    #include<algorithm>
    #include<iostream>
    #include<cstring>
    #include<cstdlib>
    #include<cstdio>
    #include<cmath>
    #include "gap.h"
    using namespace std;
    #define ll long long
    #define db double
    #define For(i,a,b) for(int i=(a);i<=(b);++i)
    #define Rep(i,a,b) for(int i=(a);i>=(b);--i)
    
    ll findGap(int T,int N) {
    	ll n=(N+1)>>1,l=0,r=1e18,ld,rd,rs=0,fl=0,len;
    	if(T==1) {
    		MinMax(l,r,&ld,&rd); l=ld; r=rd;
    		For(i,1,n-1) {
    			MinMax(l+1,r-1,&ld,&rd);
    			rs=max(rs,ld-l); rs=max(rs,r-rd);
    			l=ld; r=rd;
    			if((r-1)-(l+1)<=rs) {fl=1; break;}
    		}
    		if(!fl) rs=max(rs,rd-ld);
    		return rs;
    	}
    	else {
    		MinMax(l,r,&ld,&rd); l=ld; r=rd; len=(r-l+N-2)/(N-1);
    		ll lst=l;
    		for(ll now=l;now<r-1;now+=len) {
    			MinMax(now+1,min(now+len,r-1),&ld,&rd);
    			if(~ld) rs=max(rs,ld-lst),lst=rd;
    		}
    		rs=max(rs,r-lst);
    		return rs;
    	}
    }
    

    编译:

    g++ -g gap.cpp grader.cpp -o gap
    

    grader.cpp

    #include <stdio.h>
    #include <stdlib.h>
    
    #include "gap.h"
    
    static void my_assert(int k){ if (!k) exit(1); }
    
    static int subtask_num, N;
    static long long A[100001];
    static long long call_count;
    
    long long findGap(int, int);
    
    void MinMax(long long s, long long t, long long *mn, long long *mx)
    {
    	int lo = 1, hi = N, left = N+1, right = 0;
    	my_assert(s <= t && mn != NULL && mx != NULL);
    	while (lo <= hi){
    		int mid = (lo+hi)>>1;
    		if (A[mid] >= s) hi = mid - 1, left = mid;
    		else lo = mid + 1;
    	}
    	lo = 1, hi = N;
    	while (lo <= hi){
    		int mid = (lo+hi)>>1;
    		if (A[mid] <= t) lo = mid + 1, right = mid;
    		else hi = mid - 1;
    	}
    	if (left > right) *mn = *mx = -1;
    	else{
    		*mn = A[left];
    		*mx = A[right];
    	}
    	if (subtask_num == 1) call_count++;
    	else if (subtask_num == 2) call_count += right-left+2;
    }
    
    int main()
    {
    //	freopen("gap.in","r",stdin);
    //	freopen("gap.out","w",stdout);
    	FILE *in = stdin, *out = stdout;
    	my_assert(2 == fscanf(in, "%d%d", &subtask_num, &N));
    	my_assert(1 <= subtask_num && subtask_num <= 2);
    	my_assert(2 <= N && N <= 100000);
    	for (int i=1;i<=N;i++) my_assert(1 == fscanf(in, "%lld", A+i));
    	for (int i=1;i<N;i++) my_assert(A[i] < A[i+1]);
    	fprintf(out, "%lld
    ", findGap(subtask_num, N));
    	fprintf(out, "%lld
    ", call_count);
    }
    

    gap.h

    void MinMax(long long, long long, long long*, long long*);
    
  • 相关阅读:
    23种设计模式
    外部排序:选择置换、败者树
    java代理模式
    java中抽象类和接口的异同(原文作者:博客园 海子)
    java中的垃圾回收
    进程
    C标准库-数值字符串转换与内存分配函数
    文件操作
    字符串操作
    C指针(二)
  • 原文地址:https://www.cnblogs.com/Serene-shixinyi/p/8984759.html
Copyright © 2011-2022 走看看