题目大意:
Problem Description
Give you a number on base ten,you should output it on base two.(0 < n < 1000)
Input
For each case there is a postive number n on base ten, end of file.
Output
For each case output a number on base two.
Sample Input
1 2 3
Sample Output
1 10 11
十进制转二进制
解题思路:
按照定义,对二求余
代码:
#include <iostream> using namespace std; int main() { int a,i; int b[100]; while(cin>>a) { i=0; while(a!=0) { b[i]=a%2; a/=2; i++; } for(i--;i>=0;i--) cout<<b[i]; cout<<endl; } return 0; }